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V125BC [204]
3 years ago
15

Solve for x. PLZ WAIT FOR PHOTO

Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0
Δ = b^2 - 4.a.c = 4 - 4.6.3 = -68< 0

rootΔ = root(-68)

no real solutions :) Cause -68 not positive.

Good Luck :)
Marrrta [24]3 years ago
7 0
The answer is b. because√-68 could be factorized in -2√17
so 2+- -2√17/12 is the same that 1+- -√17/6
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5 : 36

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Does the graph represent a function? <br> Yes Or No
Vesna [10]

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Yes.

Step-by-step explanation:

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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

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                                       x+DB = 3

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Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

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3 0
3 years ago
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4 0
3 years ago
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Answer:

D

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3 years ago
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