Revenue=quantity x price= (-2p+1000) (p)= -2p^2+1000p
The maximum revenue will occur when the first derivative is zero so when 2(-2p)+1000=0;p=250
Which generates 125,000 in revenue
Try prices of 245 and 255 and you will see they both are less than 250 thereby proving the max revenue is 250
Answer:
B is the awnser
Step-by-step explanation:
I just took the etest!!!
Answer:
(amounts could be:)
Katia: $3.50
Mateo: $1.75
Step-by-step explanation:
<em>Remember that a quarter = $0.25, 4 quarters = $1.00</em>
<h3>We know that they both have 38 quarters ($9.50) </h3>
<em>after an hour of playing games in the arcade, Katia has $1.75 more than Mateo</em>
lets say that Katia has <em>(random amount)</em><em>$3.50(14 quarters) </em>and Mateo has $1.75 less than that.
$3.50 - $1.75 = $1.75
<h3>Katia has $3.50 and Mateo has $1.75.</h3>
Answer:
-4
Step-by-step explanation:
3(5-n)=27
solve
15-3n=27
subtract 15 from 2 sides
-3n=12
n=-4
Answer:
72 pages (648 discs)
Step-by-step explanation:
