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docker41 [41]
3 years ago
11

What central tendency means to find the number that occurs most often?

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:The mean is the most frequently used measure of central tendency because it uses all values in the data set to give you an average. For data from skewed distributions, the median is better than the mean because it isn't influenced by extremely large values.

Step-by-step explanation:

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Given that (7x-8)/(2x-1)(x-2) <br><br> Use Partial Fraction Decomposition to Find A and B.
koban [17]

We look for constants <em>a</em> and <em>b</em> such that

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac a{2x-1} + \frac b{x-2}

Rewrite all terms with a common denominator and set the numerators equal:

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)}{(2x-1)(x-2)} + \frac{b(2x-1)}{(x-2)(2x-1)} \\\\ \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)+b(2x-1)}{(2x-1)(x-2)} \\\\ \implies 7x-8 = a(x-2) + b(2x-1) = (a+2b)x - 2a - b

Then

<em>a</em> + 2<em>b</em> = 7

-2<em>a</em> - <em>b</em> = -8

Solve for <em>a</em> and <em>b</em>. Using elimination: multiply the first equation by 2 and add it to the second equation:

2 (<em>a</em> + 2<em>b</em>) + (-2<em>a</em> - <em>b</em>) = 2(7) + (-8)

2<em>a</em> + 4<em>b</em> - 2<em>a</em> - <em>b</em> = 14 - 8

3<em>b</em> = 6

<em>b</em> = 2

Then

<em>a</em> + 2(2) = 7   ==>   <em>a</em> = 3

and so

\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac 3{2x-1} + \frac 2{x-2}

7 0
3 years ago
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Answer:

the answer is a period

Step-by-step explanation:

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lesya [120]
928,904+0



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4 years ago
When changing a percent to the equivalent decimal you drop the percent sign and then
katrin2010 [14]
Move the decimal to the left twice.

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35.0

.35

(this is the equivalent of dividing the number by 100)
4 0
3 years ago
I will give brianly just help me
Bumek [7]

Answer:

The answer is C

Step-by-step explanation:

All I did was try to match C with F. Count how many lines you went to the right and thats your x value. Same for Y but down. Down forgot to add integers.

3 0
3 years ago
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