It would be a decimal which is 3.363636363636364 and if you convert it into a fraction it is 9090909091/25000000000 so in real terms it is 3 students per computer.
Answer: $15927.183
Step-by-step explanation:
Price of good= $29,000
Trade discount = 40½ 20¼/5
The first discount will be:
= 40½ × $29000
= $11745
Then, the price after the first discount will be:
= $29000 - $11475
= $17255
Then, the second discount will be:
= $17255 × 20¼%
= $3494.14
Then, the price after the second discount will be:
= $17255 - $3494.14
= $13760.86
The third discount will be:
= $13760.86 × 5%
= $688.043
Then, the total discount will be:
= $11745 + $3494.14 + $688.043
= $15927.183
Therefore, the trade discount is $15927.183.
Evaluate the function at 2. That is f(2).
Evaluate the function at 0. That is f(0).
the average rate of change from 0 to 2 is (f(2) - f(0))/(2 - 0)
f(x) = 120(0.1)^x
f(2) = 120(0.1)^2 = 120 * 0.01 = 1.2
f(0) = 120(0.1)^0 = 120 * 1 = 120
average rate of change = (1.2 - 120)/(2 - 0) = -118.8/2 = -59.4
Ayo,I gotta explain u complain a lot these days u make me feel tired even math u can’t solve ur own problems teachers u know everything but when I ask u a questioning become my student ur boring- I tried hhh
