3 years ago

Pls help me, pleaseeeee

1 answer:

6 0

The hypotenuse is $\sqrt{a^2+b^2}= c$
a= one side
b= another
c= hypotenuse

$\sqrt{ 12^{2} +12^{2} }$
$\sqrt{144+144}$
$\sqrt{288}$
About 17
17+12+12 = 41

41 feet

You might be interested in

50 Points

Harlamova29_29 [7]

The answer is C because it moves 5 right and 10 up so it’s still positive on both 5 is x and 10 is y

4 0

3 years ago

How many solution does this equation have -5j = -6j - 4

Nataly_w [17]

Answer:

Step-by-step explanation:

All variable terms are to the first power. You can prove this by solving:

-5j = -6j - 4

4 = -1j

j = -4 (One answer)

6 0

3 years ago

Hellllllllllllllllllllllllllp me plsssssssssssssssssssssssss

Marina CMI [18]

first one: 1 1/2 pints

second: 44 months

3 0

3 years ago

Solve for a. 15(25−5a)=4−a <br> A- 0 <br> B-−1 <br> C-all real numbers<br> D- no solution

Anon25 [30]

The answer is d- no solutions

7 0

3 years ago

Read 2 more answers

La matemática financiera experimentó grandes avances con la creación de la banca y los negocios creados por los emprendedores. E

Tresset [83]

Answer:

c = $\frac{1}{10}$

f= 1500

Step-by-step explanation:

Tenemos la siguiente ecuación

$C = f+cm$

Tenemos los siguientes valores para m=15000, c = 3000 y para m = 20000, c=3500. Es decir, tenemos las siguientes ecuaciones

$3000=f+c15000, 3500=f+c20000$

Si restamos la segunda ecuación de la primera, tenemos que

$3500-3000 = f-f+(20000c-15000c)$

Luego

$500 = 5000c$

Entonces $c = \frac{500}{5000} = \frac{1}{10}$

Si tomamos la primera ecuación, tenemos que $3000-\frac{15000}{10} = f$ . Es decir,

$3000-1500 = f = 1500$

Esta solución, al plantear 2 ecuaciones y dos incógnitas, plantea un sistema dos por dos.

8 0

3 years ago