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alina1380 [7]
3 years ago
11

DESPERATE! PLEASE HELP!! BRAINLIEST! Show how you got answer please!

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0
43 units
count all the square boxes. count the boxes covering more than half and leave the boxes covering less than half. I hope it's correct.
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I need help on all 3 of these questions
Jobisdone [24]
1) C is because it’s exactly double the size in both width and length while the others are only gaining one or the other. For example - the a length of the squares is 5 and the length on c is 10, the base on a is 3 long, the base on c is 6. The width on a is 1 and the width on c is 2. You can put these into fractions 5/10 3/6 1/2 but they all equal 1/2. So it’s double the size of a.

5 0
3 years ago
Bryan is buying notebooks and pens at an office supply store. Notebooks cost $3.59 and pens cost $1.49. He can spend up to $13 o
nordsb [41]
3.59x+1.49y=13.00
that should help
4 0
3 years ago
Read 2 more answers
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y
KonstantinChe [14]

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

= 1.96^2\times \frac{210^2}{15^2}

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

8 0
3 years ago
X - x equals ?............​
Paul [167]

Answer:

0

Step-by-step explanation:

if x stade for any number like 5 then it will be 5-5=0

hope this helps you out need more help ask me

4 0
4 years ago
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