Answer:
0.8%.
Step-by-step explanation:
Given:
At the start of the month, the value of an investment was $73.42.
By the end of the month, the value of the investment changed by a loss of $13.53.
Question asked:
What was the value, in dollars, of the investment at the end of the month?
What was the percent loss?
Solution:
At the start of the month, the value of an investment = $73.42.
Loss = $13.53.
<u><em>The value, of the investment at the end of the month = The value of an investment at the start of the month - loss</em></u>
The value, of the investment at the end of the month = $73.42 - $13.53
= $59.89
Thus, the value, of the investment at the end of the month is $59.89.
Now, we will find percent loss:-
Thus, percent loss on investment by the end of the month is 0.8%.
Answer:
840
Step-by-step explanation:
Heres the easiest way to figure this out. You deposit $700 dollars into your account, correct? So, the annual interest rate is 4%. Take 700 dollars and multiply that by 4 percent. You get $28. So, EVERY. SINGLE. YEAR. you get 28$. So, multiply 28 by 5. Thats $140. Then, add 140 into 700, and you get 840.
Hope this helped!
Answer:
B. 1 1/7
Step-by-step explanation:
-9 2/7-(-10 3/7)
=-9 2/7+10 3/7
=1 1/7
Therefore, B. 1 1/7
Answer:
would bud but cant
Step-by-step explanation:
The correct question is
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8-x^-1 intersect are the solutions of the equation 4−x = 8-x^-1<span>.
Part B: Make tables to find the solution to 4−x = </span>8-x^-1<span>. Take the integer values of x between −3 and 3.
Part C: How can you solve the equation 4−x = </span>8-x^-1 graphically?
Part A. We have two equations: y = 4-x and y = 8-x^-1
Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when
4-x = 8-x^-1
This is where the two graphs will cross and that is the common point that satisfies both equations.
Part B
see the attached table
the table shows that one of the solutions is in the interval [-1,1]
Part C To solve graphically the equation 4-x = 8-x^-1
We would graph both equations: y = 4-x and y = 8-x^-1
The point on the graph where the lines cross is the solution to the system of equations.
using a graph tool
see the attached figure N 2
the solutions are the points
(-4.24,8.24)
(0.24,3.76)
