Given:
The pair of expressions in the options.
To find:
The two expressions are equivalent for any value of y.
Solution:
Two expressions are equivalent for any value of y, iff they are equivalent.
![3(3y+3)=3(3y)+3(3)](https://tex.z-dn.net/?f=3%283y%2B3%29%3D3%283y%29%2B3%283%29)
![3(3y+3)=9y+9](https://tex.z-dn.net/?f=3%283y%2B3%29%3D9y%2B9)
Clearly,
is not equivalent to
or
. So, options A and B are incorrect.
![9(y+3)=9(y)+9(3)](https://tex.z-dn.net/?f=9%28y%2B3%29%3D9%28y%29%2B9%283%29)
![9(y+3)=9y+27](https://tex.z-dn.net/?f=9%28y%2B3%29%3D9y%2B27)
![9(y+3)=27+9y](https://tex.z-dn.net/?f=9%28y%2B3%29%3D27%2B9y)
The expression
is not equivalent to
. So, option C is incorrect.
The expression
is equivalent to
.
Therefore, the correct option is D.
Dik butter lol this is fun I am getting points for these answers
Answer:
-1 Not in domain
0 In domain
1 In domain
Step-by-step explanation:
The domain for the square root function is all positive numbers including (0). The domain is the set of real numbers which when substituted into the function will produce a real result. While one can substitute a negative number into the square root function and get a result, however, the result will be imaginary. Therefore, the domain for the square root function is all positive numbers. It can simply be expressed with the following inequality:
![x\geq0](https://tex.z-dn.net/?f=x%5Cgeq0)
Therefore, one can state the following about the given numbers. Evaluate if the number is greater than or equal to zero, if it is, then it is a part of the domain;
-1 => less than zero; Not in domain
0 => equal to zero; <em> </em>In domain
1 => greater than zero: In domain
This is the quadratic formula.
Answer:
Only Francesca is correct
Step-by-step explanation:
I just did it