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miss Akunina [59]
3 years ago
9

Please help me!!!! You only have to answer number 1!!!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Given : A social media website has currently = 1,000 members.

           In each month number of members gets triple.

To find: Equation that represents number of members m belongs to site.

Solution: Because we are given, each month the number of members gets triple, that means each month we can multiply by 3 to the number of members of previous month.

For first month, we would multiply 1,000 by 3.

For second month, we would multiply 1,000 by 3 *3.

For second month, we would multiply 1,000 by 3*3*3.

Each month one factor of 3 is being increasing.

We could write those 3's as exponents of 3.

Like 1000*3 = 1000*3^1

1000 * 3^2.

1000 * 3^3.

As many months as many 3's are there.

So, the exponent of 3 is represnts the number of months.

Let us take a variable for number of month by n.

So, we could setup an equation for number of members m belongs to site on a particular month n as

m= 1000 (3)^n

This is our final equation.

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A square is divided into smaller squares and portions are shaded. What is the are of the shaded portion?​
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Step-by-step explanation:

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Solve: 6 - x=-12 )<br> A) -18 <br>B) C 0 <br>D) 18​
Luda [366]

Answer:

D) 18

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

4 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2-cm and a standard dev
Varvara68 [4.7K]

Answer:

The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.

Step-by-step explanation:

We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.

Let \bar X = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean length of rods = 259.2 cm

           \sigma = standard deviaton = 2.1 cm

           n = sample of steel rods = 17

Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(\bar X > 259 cm)

 

     P(\bar X > 259 cm) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{259-259.2}{\frac{2.1}{\sqrt{17} } } ) = P(Z > -0.39) = P(Z < 0.39)

                                                                = <u>0.65173</u>

The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.

8 0
4 years ago
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