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miss Akunina [59]
3 years ago
9

Please help me!!!! You only have to answer number 1!!!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Given : A social media website has currently = 1,000 members.

           In each month number of members gets triple.

To find: Equation that represents number of members m belongs to site.

Solution: Because we are given, each month the number of members gets triple, that means each month we can multiply by 3 to the number of members of previous month.

For first month, we would multiply 1,000 by 3.

For second month, we would multiply 1,000 by 3 *3.

For second month, we would multiply 1,000 by 3*3*3.

Each month one factor of 3 is being increasing.

We could write those 3's as exponents of 3.

Like 1000*3 = 1000*3^1

1000 * 3^2.

1000 * 3^3.

As many months as many 3's are there.

So, the exponent of 3 is represnts the number of months.

Let us take a variable for number of month by n.

So, we could setup an equation for number of members m belongs to site on a particular month n as

m= 1000 (3)^n

This is our final equation.

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azamat

Answer:

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Answer:

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Step-by-step explanation:

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Read 2 more answers
For each sentence below, find the value of x that makes each sentence true.
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<u>ANSWER</u>

1. x=\frac{1}{2}


2. x=1


<u>QUESTION 1</u>

The first sentence is (5^{\frac{1}{5}})^5=25^x.


Recall that;

(a^m)^n=a^{mn}


We simplify the left hand side by applying this property to get;


5^{\frac{1}{5}\times 5}=25^x.


\Rightarrow 5^{1}=25^x.


We now rewrite the right hand side too in an index form to obtain;


\Rightarrow 5^{1}=5^{2x}

We now equate the exponents to get;

\Rightarrow 1=2x.


\Rightarrow \frac{1}{2}=x


\Rightarrow x=\frac{1}{2}.


<u>QUESTION 2</u>

The second sentence is (8^{\frac{1}{3}})^2=4^x


We simplify the left hand side first to get;

(2^{3\times \frac{1}{3}})^2=4^x


2^2=4^x


We now rewrite the left hand side too in index form to obtain;


2^2=2^{2x}

We equate the exponents to get;

2=2x


This implies that;


1=x

or

x=1

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Step-by-step explanation:

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