Answer:
D
Step-by-step explanation:
Only one - to - one and many to one relations are functions.
2
![2x^2+7x-10 = x+5 2x^2+7x-15 y2x^2+6x-15](https://tex.z-dn.net/?f=2x%5E2%2B7x-10%20%3D%20x%2B5%0A%0A2x%5E2%2B7x-15%0A%0Ay2x%5E2%2B6x-15%20)
Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)
Answer:
![(x+5)^{2} (x-2)](https://tex.z-dn.net/?f=%28x%2B5%29%5E%7B2%7D%20%28x-2%29)
Step-by-step explanation:
1) Factor
using polynomial division.
![(x^{2} +10x+25)(x-2)](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B10x%2B25%29%28x-2%29)
2) Rewrite
in the form
, where a = x and b = 5.
![(x^{2} +2(x)(5)+5^{2} )(x-2)](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B2%28x%29%285%29%2B5%5E%7B2%7D%20%29%28x-2%29)
3) Use Square of Sum:
.
![(x+5)^{2} (x-2)](https://tex.z-dn.net/?f=%28x%2B5%29%5E%7B2%7D%20%28x-2%29)
Answer:
Y≈4.6
Step-by-step explanation:
Because the hypotenuse is 9rad2 and the angle opposite of it is a 90. You can deduce it is a 90-45-45. From this you can tell the legs are 9. You then do 9 tan 26 to get about 4.4, and after this you subtract it from 9.