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OverLord2011 [107]
3 years ago
13

F(x)=x3+8x2+5x−50 factored

Mathematics
1 answer:
Luda [366]3 years ago
4 0

Answer:

(x+5)^{2} (x-2)

Step-by-step explanation:

1) Factor x^3} +8x^{2} +5x-50 using polynomial division.

(x^{2} +10x+25)(x-2)

2) Rewrite x^{2} +10x+25 in the form a^{2} +2ab+b^{2}, where a = x and b = 5.

(x^{2} +2(x)(5)+5^{2} )(x-2)

3) Use Square of Sum: (a+b)^{2} =a^{2} +2ab+b^{2}.

(x+5)^{2} (x-2)

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A hydro company is laying down power lines in the ground. They have two sections of cable so far that are 325.0 m and 430.0 m lo
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The length of extra cable that is required to connect the two pieces of existing cable is equal to 182 meters.

<h3>How to determine the length of extra cable?</h3>

In order to determine the length of extra cable that is required to connect the two pieces of existing cable, we would apply the law of cosine as follows:

B² = A² + C² - 2(A)(C)cosB

Substituting the given parameters into the formula, we have;

B² = 325.0² + 430.0² - 2(325.0)(430.0)cos23

B² = 105,625 + 184,900 - 279,500(0.9205)

B² = 290,525 - 257,279.75

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B = √33,245.25

B = 182.33 ≈ 182 meters.

Read more on cosine law here: brainly.com/question/11000638

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2 years ago
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Answer:

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