Given mean = 0 C and standard deviation = 1.00
To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.
z= 
So, P(x<0.53) = P(z<0.53) = 0.701944
Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665
For finding probability for in between values, we have to subtract smaller one from larger one.
P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465
P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436
P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23) =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918
X = cost of car before tax
Total cost = (cost of car before tax) + (tax amount)
Total cost = x + 5% of x
Total cost = x + 0.05x
Total cost = 1.05x
The total cost is given to be $14,512, which means
<span>Total cost = 1.05x = 14512
</span>
1.05x = 14512
1.05x/1.05 = 14512/1.05
x = 13,820.95238
x = 13,820.95
The total cost of the car before tax, to the nearest cent, is $13,820.95
Answer:
original (7,-4)
Final (7,2)
Step-by-step explanation:
I'm not 100% positive considering I haven't done this type of work in a long time.
Answer:
In 2013 there were approximately 2.2 million cars for sale.
Step-by-step explanation:
Since the number of cars is decreasing by 23% per year, it is a decay model. This types of decay can be expressed in the following expression:
Where x is the year, cars(2007) is the number of cars in 2007. Applying this data we have:
If we want to know the number of cars in 2013, we need to apply that value to x and solve the expression.
In 2013 there were approximately 2.2 million cars for sale.
