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Kitty [74]
3 years ago
8

In 2007, there were more than 8.14 million cars for sale. The number of cars then decreased by 23% per year. Write an exponentia

l growth or decay model given by the number of c cars over t years after 2007. Use this model to estimate how many cars there were in 2013?
Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

In 2013 there were approximately 2.2 million cars for sale.

Step-by-step explanation:

Since the number of cars is decreasing by 23% per year, it is a decay model. This types of decay can be expressed in the following expression:

cars(x) = cars(2007)*(1 - 0.23)^{x - 2007}

Where x is the year, cars(2007) is the number of cars in 2007. Applying this data we have:

cars(x) = 8.14*(0.77)^{x - 2007}

If we want to know the number of cars in 2013, we need to apply that value to x and solve the expression.

cars(2013) = 8.14*(0.77)^{2013 - 2007}\\cars(2013) = 8.14*(0.77)^{5} = 2.20332

In 2013 there were approximately 2.2 million cars for sale.

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Explain which variables would be included when using technology to calculate the present value of a lump sum and to calculate th
koban [17]

Answer:

a. Present value of a lump sum =

PV = FV / ( 1 + i )ⁿ

b. Present value of an annuity =

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ )) / r)

Step-by-step explanation:

a. Present Value of a Lump sum =

PV = FV / ( 1 + i )ⁿ

Where variables in the formula are explained as follows

PV = Present Value of the given amount today

FV = Future Value of the given amount

i = Discount rate

n = Number of periods

b. Present value of an annuity is given as:

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ)) / r)

The variables in the equation are explained as the follows:

P = the present value of annuity

PMT = Payment per period or the amount in each annuity payment

r =  the interest or discount rate

n = total number of periods or the number of payments left to receive

8 0
3 years ago
10. 2x + 7y = 1<br> 2x - 4y = 12<br> Solve for y
adoni [48]

Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

2x\ +\ 7y\ =\ 1    ....(1)

2x\ -\ 4y\ =\ 12  ....(2)

So, to solve for y, first we solve for x in equation (2):

2x-4y=12

⇒2x=12+4y

Dividing both sides by 2,

⇒x=6+2y            

Now, substituting the value of x  in equation (1):

2x+7y=1

⇒2(6+2y)+7y=1

⇒12+4y+7y=1

⇒12+11y=1

⇒11y=1-12

⇒11y=-11

Dividing both sides by 11,

⇒y=-1

Therefore, the solution for y = -1.

7 0
3 years ago
Please help I really do not understand this yeah I can be weird sometimes but please help will mark the correct answers brainies
NISA [10]

Answer:

Step-by-step explanation:

1.0.39

2.0.33

3.Loose

4.0.14

I did the first four... hope that helps

3 0
3 years ago
Regina, Phil, and Joseph each wrote expressions to represent their hourly earnings for an after-school job where h represents th
Vladimir79 [104]

Answer:

Disagree

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money

Step-by-step explanation:

The given expression for the hourly earnings of Regina, Phil and Joseph are as follows;

Regina: 6.50·h + 16

Phil: 3·(2.5·H + 5)

Joseph: 7.50·h + 10

The number of hours worked = h

The hourly earnings for Phil equated to the hourly earnings of Joseph gives;

3·(2.5·H + 5) = 7.50·h + 10

Simplifying we get;

3 × 2.5·h + 3 × 5 = 7.50·h + 10

7.5·h + 15 = 7.50·h + 10

Which gives

15 =  10 + 5 = 10 which is not correct.

Therefore, when both Phil and Joseph works the same number of hours, in the week, Phil will earn 5 units more Joseph

However, we have that, where Joseph works extra 5/7.5 or 2/3 hours more than Phil, every week, they will earn the same amount of money every week.

Therefore, it is possible for Phil and Joseph to earn the same amount of money when Joseph works extra 2/3 hours more than Phil which gives;

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money.

3 0
3 years ago
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