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katen-ka-za [31]
3 years ago
11

Through the point (3,1.2) that has an y intercept of 3

Mathematics
1 answer:
topjm [15]3 years ago
3 0

Answer:

y = -0.6x +3

Step-by-step explanation:

equation of the line through point (3, 1.2) and y-interecept of 3

y= mx+b

m is the slope and b is thhe y-intercept

y = mx + 3

between points (3, 1.2) and (0,3) the slope is

m= (y2-y1)/ (x2-x1) = (1.2-3) / (3-0) = -1.8/3 = -0.6

y = -0.6x +3

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3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

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