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kiruha [24]
3 years ago
11

Help! Clear the fractions

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

x = - \frac{27}{20}

Step-by-step explanation:

Given

\frac{5}{6} x + 2 = \frac{7}{8}

Multiply through by 24 ( the LCM of 6 and 8 ) to clear the fractions

20x + 48 = 21 ( subtract 48 from both sides )

20x = - 27 ( divide both sides by 20 )

x = - \frac{27}{20}

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I don't know how to do this, can someone explain me ​
Kaylis [27]

Answer:

-8+√5a-5 =-3

√5a-5 =5

a=6

5(6)=30

30-5=25

√25=5

-8+5=-3

5 0
4 years ago
Solve the following inequality: n + 6 is less than or equal to 3
Rainbow [258]

Answer:

n+6 is less than or equal to 3

Step-by-step explanation:

this answer is n is less than or equal to -3

4 0
3 years ago
Choose the lowest common denominator.
Brilliant_brown [7]

1) 8

2) -\frac{3}{4}=-\frac{6}{8}, so it is equal to -\frac{6}{8}+\frac{5}{8}

3) 1/8

4 0
2 years ago
Perform the indicated operations. Reduce the answers to lowest terms .<br>​
kozerog [31]

Step-by-step explanation:

1. (2+4+1)/9 = 7/9

2. 2 1/3 + 2/3 = 2 + (1+2)/3 = 2 + 3/3 = 2+1 = 3

3. 1 1/5 + 2 3/5 = 1+2 + 1/5 + 3/5 = 3 + (1+3)/5 =

3 4/5

4. 5/6 + 2/10 + 1/5 = 5/6 + 1/5 + 1/5 = 5/6 + 2/5

= (5×5)/(6×5) + (2×6)/(5×6)

= 25/30 + 12/30

= (25+12)/30

= 37/30 = 1 7/30

5. 3 1/2 + 4 2/3

= 3+4 + 1/2 + 2/3

= 7 + (1×3)/(2×3) + (2×2)/(3×2)

= 7 + 3/6 + 4/6

= 7 + (3+4)/6 = 7 7/6 = 8 1/6

6. 9/13 - 5/13 = (9-5)/13 = 4/13

7. 7 6/8 - 5 2/8

= (7-5) + (6/8 - 2/8)

= 2 + 4/8

= 2 1/2

8. 2/3 - 3/7

= (2×7)/(3×7) - (3×3)/(7×3)

= 14/21 - 9/21 = (14-9)/21 = 5/21

9. 11 1/5 - 5 4/5

= 10 6/5 - 5 4/5

= (10-5) + (6/5 - 4/5)

= 5 + 2/5 = 5 2/5

10. 15 4/5 - 7 7/10

= (15-7) + (4/5 - 7/10)

= 8 + (4×2)/(5×2) - 7/10

= 8 + 8/10 - 7/10

= 8 + 1/10

= 8 1/10

6 0
3 years ago
25 – 4.33<br>7 + (1 - 100)​
Sidana [21]

Answer:

25 – 4.33 = 20.67

7 + (1 - 100)​ = -92

Step-by-step explanation:

First one) Simply use your knowledge of integers and decimals to solve this. You can even start by drawing a number line and practising with that before beginning to do harder problems.

Second one) Just like the first one but use PEDMAS, BEDMAS or BODMAS and make sure to solve the brackets first.

6 0
3 years ago
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