Answer:
1) 2(t+1)(t−7)
2) 7 months
Step-by-step explanation:
Answer:
Step-by-step explanation:
8x = 9x - 7
-x = -7
x = 7
9(7)-7= 63-7=56
8(7)= 56
13y+7+56=180
13y+63=180
13y=117
y=9
13(9)+7= 117+7= 124
5y-11+56=90
5y+45=90
5y=45
y=9
5(9)-11+9(7)-7= z
45-11+63-7=z
34+56=z
90=z
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
x = 6
Step-by-step explanation:
-5(-2) + [8(-2)/4] = 10+(-16/4) = 10-4 = 6
One train will be travelling at 60 mph, and the other train will be travelling at 70 mph. 70 * 5.5 = 385, 60 * 5.5 = 330. 330 + 385 = 715