Answer:
I hope this helps
Step-by-step explanation:
So the way to handle a problem like this is to rewrite the three numbers in terms of their relationship to one of the three numbers. Let's call the numbers x, y, and z, where x is the first number, y is the second, and z is the third.
We know x + y + z = 83.
Since the third number is twice the second, we say that z = 2y.
Since the second number is seven less than the first, we say that y = x - 7. We can rewrite this as x = y + 7.
Now all three can be written in terms of y.
x + y + z = 83
(y + 7) + y + 2y = 83
4y + 7 = 83
4y = 76
y = 19
The second number is 19. The first is 19 + 7 or 26, and the third is 2 times 19 or 38.
A check reveals that 26 + 19 + 38 = 83.
