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stepan [7]
3 years ago
9

Please answer number 4

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

i don't know, bro..

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I need help. Please help me!
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Answer:

Step-by-step explanation:

omg are you in school do you have to go on the board bc you dead meat

7 0
2 years ago
16/9(1.2b)=4.8(20/3)<br> solve
mart [117]

\frac{16}{9}(1.2b)=4.8( \frac{20}{3})

Multiply 4.8 into (20/3), and multiply 16/9 with (1.2b)

\frac{19.2b}{9} = \frac{96}{3}

\frac{19.2b}{9} = 32  Multiply 9 on both sides

19.2b = 32(9)

19.2b = 288          Divide 19.2 on both sides

b = 15

4 0
3 years ago
Marybeth opened her bank account with $125. She spends $10 every 3 weeks. Write an equation that represents the balance of her a
Fantom [35]

Answer:if she spends $10 dollars every 3 weeks it will take her 45 weeks to have her only $5 dollars left in her bank account

8 0
3 years ago
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A photograph was enlarged and made into a poster using the scale factor of 2. The photograph is 5 inches by 11 inches. What is t
arsen [322]

Answer:

the area is 55

Step-by-step explanation:

5 0
3 years ago
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Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
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