Actually, it is false. P-waves arrive first and then S-waves arrive.
Since after crossing a red and a white flower produced pink flowers, the red color trait shows an incomplete dominance and has a genotype of Rr.
Using the Punnett to determine the cross between pink and white flowers:
| R | r |
r | Rr | rr |
r | Rr | rr |
The results indicate that the cross between pink and white flowers will produce a ratio of 1:1
Rr x rr
Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
Answer:
Primase
Explanation:
Primer needed to initiate DNA replication is PRIMASE.
It aids replication by ensuring that a short stretch of nucleic acid are usually complementary to the template which aids the process.
It also helps to provides and make readily available the 3' end for DNA polymerase to work on during the process of replication
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