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2 years ago

13

What the rate of change of the function y = 3/2x + 5?

1 answer:

AfilCa [17]2 years ago

6 0

Answer: 3/2

Step-by-step explanation: Rate of change is the same thing as the slope.

You might be interested in

A. 5°<br>B. 35°<br>C. 31°<br>D. 7°

MrRissso [65]

Answer:

(2x +30) and (3x -5) (they're opposite to eachother, so they're equal)

2x + 30 = 3x - 5 (set them equal to eachother, then subtract 3x from both side)

-1x = -35 (divide both sides by -1 to isolate x)

x = 35 or B (this is your answer)

Step-by-step explanation:

I hope this helps :))

3 0

3 years ago

What’s the measure of this angle

pashok25 [27]

First, write the expression.
180=(x+96)+5x
Second, add all coefficients.
180=6x+96
Subtract 96 from each side.
180-96=6x+96-96
84=6x
Divide both sides by 6.
14=x
Now that you have found the value of x, substitute x to solve the angles.
The first angle:
x+96
14+96=110 degrees
The second angle:
5*x
5*14=70 degrees

3 0

3 years ago

Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s

Margaret [11]

Answer:

$QR = 6.0033$

$QS = 8.22$

$RS = 6.0033$

QRS is isosceles

Step-by-step explanation:

Given

See attachment for complete question

From the attachment, we have the following parameters $QR = \sqrt{(-3-0)^2+(-5.2-0)^2}$

$QR = \sqrt{9+27.04}$

$QS = \sqrt{(-3-5)^2+(-5.2-(-3.322))^2}$

$QS = \sqrt{64+3.53} = \sqrt{67.53$

$RS = \sqrt{(0-5)^2 + (0 - (-3.322))^2}$

$RS = \sqrt{(25 + 11.04}$

Solving further, we have:

$QR = \sqrt{9+27.04}$

$QR = \sqrt{36.04}$

$QR = 6.0033$

$QS = \sqrt{64+3.53} = \sqrt{67.53}$

$QS = 8.22$

$RS = \sqrt{25 + 11.04}$

$RS = \sqrt{36.04}$

$RS = 6.0033$

From the calculations;

$RS = QR = 6.0033$

<em>This means that: QRS is isosceles</em>

8 0

2 years ago

Help 1-8 I need answers and show work!!!

agasfer [191]

Answer:

hope this helps you out good luck

6 0

2 years ago

Select the correct answer from the drop-down menu.

ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$ .

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

$=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

$=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

$=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$ .

Given the quotient of $-8x^2y^3 \div xy$ is same as the product of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0

3 years ago