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3 years ago

PLEASE ANSWER ASAP FOR BRAINESLT!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

5 0

Answer:

Step-by-step explanation:

Circumference = Pi * radius^2

The radius is half of the diameter, 23.

I am Lyosha [343]3 years ago

5 0

Answer:

It's c

Step-by-step explanation:

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A recipe has a ratio of 2 cups of drink mix to 5 cups of water.

Karo-lina-s [1.5K]

Answer:

1:2.5

Step-by-step explanation:

unit rate means first number is 1

52 cups to five cups is a ratio of 2:5 or 2/5

to find unit rate set up proportion

2/5 = 1/x

cross multiply to get 5= 2x

solve for x= 2.5

unit rate is 1/2.5

3 0

3 years ago

Read 2 more answers

Check all that apply please

luda_lava [24]

Answer: A & B

Step-by-step explanation:

$\sqrt{5} *\sqrt{5} = \sqrt{5*5} = \sqrt{25} = 5$

7 0

4 years ago

Hannah converts a fraction to a decimal. What do you know about that decimal?

r-ruslan [8.4K]

The answer to this will be,

c. It will terminate.

7 0

4 years ago

Find (-3/7) divided (-1 1/14)

Andrews [41]

Answer:

2/5

Step-by-step explanation:

first, we convert the mixed fractions to improper fractions,

$-1\frac{1}{14}=\frac{15}{14}$

so then we find what $-\frac{3}{7}$ $\div$ $-\frac{15}{14}$

$-\frac{3}{7}$ $\div$ $-\frac{15}{14}$ = $-\frac{3}{7} * -\frac{14}{15}$

and that equals $\frac{3*14}{7*15}$ , which equals $\frac{42}{105}$ . We can simplify that to 2/5

3 0

3 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago