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Alex777 [14]
3 years ago
15

The equation K = mv2 represents the energy an object has based on its motion. The kinetic energy, K, is based on the mass of the

object, m, and the velocity of the object, v. Lashandra is given K and v for 10 different objects. In order to make solving more efficient, she solves the equation for m : m = . After attempting to determine the mass of a few objects, Lashandra realizes there must be something wrong with her formula. What is Lashandra’s error? She should have multiplied by 2 instead of dividing by 2. She should have multiplied by instead of dividing by 2. She should have used the square root to move the squared term to the other side of the equation. She should have squared the K when moving the v2 to the other side of the equation.
Mathematics
2 answers:
docker41 [41]3 years ago
6 0
<span>The answer is She should have multiplied by 2 instead of dividing by 2.
First one.</span>
stealth61 [152]3 years ago
4 0

Answer:

She should have multiplied by 2 instead of dividing by 2.

Step-by-step explanation:

Note: The given equation is incorrect and second equation is missing.

Consider the given equation is

k=\dfrac{1}{2}mv^2         ...(i)

The formula find by Lashandra is

m=\dfrac{k}{2v^2}

We need to find the Lashandra’s error.

Multiply both sides by 2 in equation (i).

2k=mv^2

Divide both sides by v^2.

\dfrac{2k}{v^2}=m

It means, the formula find by Lashandra is incorrect. She should have multiplied by 2 instead of dividing by 2.

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Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
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Answer:

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Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

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Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

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This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

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Step-by-step explanation:

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