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GalinKa [24]
3 years ago
9

Identify like terms. (a) 3x, 4y, -2x help

Mathematics
1 answer:
kkurt [141]3 years ago
6 0
3x and -2x are like terms because they both have the variable X
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Step-by-step explanation:

4 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
15<br>a) 5<br>5 +<br>8<br>27<br>of 1<br>+<br>99<br>5​
velikii [3]

Answer:

5 5 + 8 27 of 1 + 99 5​= 150

Step-by-step explanation:

Add the expressions.

7 0
3 years ago
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nika2105 [10]

Answer:10:11 am

Step-by-step explanation:

3 0
3 years ago
Simplify square root of 8^17
damaskus [11]

Answer:

it should be somewhere along the lines of 2.25

Step-by-step explanation:

4 0
3 years ago
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