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3 years ago

Write the equation of a line that is parallel to y=9, that passes through the point (3,-8)

Mathematics

1 answer:

lisov135 [29]3 years ago

4 0

Answer:

y = -8

Step-by-step explanation:

If the equation is parallel to y = 9, the you already know that the equation must be y = some value. It passes through the point (3,-8). Just put that y value into the equation to get y = -8

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Hair color is an inherited trait. In Marci's family, her mother has brown hair. Her father has blonde hair. The family has 6 chi

xenn [34]

Answer:

the number of children has red or brown hair is $\frac{2}{3}$ .

Step-by-step explanation:

We have been given that in Marci's family there are total 6 children.

Out of 6 children

Number of children have blonde hair = $\frac{1}{3}$

Number of children have red hair = $\frac{1}{6}$

Number of children have brown hair = $\frac{1}{2}$

Since, we have to find the fraction of children has red or brown hair= $\frac{1}{6}+\frac{1}{2}=\frac{4}{6}=\frac{2}{3}$

Hence, the number of children has red or brown hair is $\frac{2}{3}$

6 0

3 years ago

What is the area of the triangle?

allsm [11]

Answer:

24 square units

Step-by-step explanation:

1) the area can be calculated using the formula:

A=0.5*a*h, where a- base, h-height;

2) if a=8, h=6, then the required area is:

A=0.5*8*6=24 [units²].

5 0

2 years ago

Read 2 more answers

Find the area of the shaded portion of the figure. Each vertex of square ABCD is at the center of a circle. Round your answer to

IrinaK [193]

Given:

Each circle has a diameter of 2 inches each.

The outer square has a side length of 4 inches and the square ABCD has a side length of 2 inches.

To find:

The area of the shaded region.

Solution:

Each circle has a diameter of 2 inches. The square ABCD is at the center of each circle so it has a side length of 1 inch.

To determine the area of the shaded region, we subtract the area of the quarter-circles in the square ABCD from the area of the square ABCD.

The area of a quarter-circle $=\frac{\pi r^{2} }{4} .$

All the quarter-circles have a radius of 1 inch.

The area of 1 quarter-circle $=\frac{\pi r^{2} }{4} = \frac{\pi (1^{2}) }{4} = \frac{3.1415}{4} .$

The area of 4 quarter-circles $=4(\frac{3.1415}{4}) = 3.1415.$

So the area of the quarter-circles in the square ABCD is 3.1514 square inches.

The area of a square $= a^{2} .$

The area of square ABCD $=2^{2} =4.$

The area of the shaded region $=4-3.1415=0.8585.$

The area of the shaded region is 0.8585 square inches.

3 0

3 years ago

Please help i don’t know if I’m doing this right

marta [7]

Answer:

x = 41

Step-by-step explanation:

a^2 + b^2 = c^2

9^2 + 40^2 = c^2

81 + 1600 = c^2

c^2 = 1681

c = 41

3 0

3 years ago

Read 2 more answers

MATHEMATICS

sukhopar [10]

Answer:

1. u = 2, v = -1.5

2. y = -7, x = -3

Step-by-step explanation:

1) For the following simultaneous equation, we have;

5·u + 2·v = 7....................(1)

2·u - 2·v = 7......................(2)

Adding equation (1) to equation (2), gives;

5·u + 2·v + 2·u - 2·v = 14

5·u + 2·u + 2·v- 2·v = 14

7·u = 14

u = 14/7 = 2u = 2

u = 2

From equation (1), we have;

5·u + 2·v = 7 substituting u = 2 gives;

5×2 + 2·v = 7

2·v = 7 - 5×2 = 7 - 10 = -3

v = -3/2 = -1.5

v = -1.5

3·x - 4·y = 19....................(1)

4·x - 5·y = 23.......................(2)

Multiplying equation (1) by 4 and equation (2) by 3 gives;

For equation (1)

4 × (3·x - 4·y) = 4 ×19

12·x - 16·y = 76...........................(3)

For equation (2)

3 × (4·x - 5·y) = 3 × 23

12·x - 15·y = 69...........................(4)

Subtracting equation (3) from equation (4) gives;

12·x - 15·y - (12·x - 16·y) = 69 - 76 = -7

12·x - 15·y - 12·x + 16·y = 69 - 76 = -7

12·x - 12·x - 15·y + 16·y = -7

y = -7

Substituting the value of y = -7 in equation (1), we have;

3·x - 4·y = 19 = 3·x - 4×(-7) = 19

3·x - 4×(-7) = 19

3·x + 28 = 19

3·x = 19- 28 = -9

x = -9/3 = -3

x = -3.

7 0

4 years ago