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ICE Princess25 [194]
3 years ago
15

PLease, help me in This!!

Mathematics
2 answers:
Ede4ka [16]3 years ago
5 0

Answer:

y = x + 5

Step-by-step explanation:

To solve this, first find the slope. To find the slope, use this formula:

m = (y2-y1)/(x2-x1)

Here, m is the slope and (x1, y1) and (x2, y2) are two points. You can use any two points on the graph to find the slope. Here, I will use (0,5) and (1,6)

m = (6-5)/(1-0) = 1/1 = 1

The slope is equal to 1. What this means (and you can confirm on your graph) is for every one unit you go up (y value), you go one unit over (x-values), to make the line.

Now, you need to find your y-intercept. Your y-intercept is what number the line crosses when x=0. Here you have a graph, so you can see when x = 0, y=5.

Now, to put it all together, you need to write the equation of your line. To write the equation, you use something called slope-intercept form. This just means your equation contains the slope and the y-intercept. It looks like this: y=mx+b, where m is your slope and b is your y-intercept. So, if your slope was 3 and your y-intercept was 8, your equation would be y=3x+8

Because your slope is 1, and any number (except 0) multiplied by 1 is just that number, you don't need to write 1 next to x. Your y-intercept is 5, so the equation of your line would be y = x + 5.

scZoUnD [109]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Look at where the arrow is coming from to where it ends

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Step-by-step explanation:

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Step-by-step explanation:

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<em>Comment on the question</em>

Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.

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