<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Answer:62
Step-by-step explanation:
Surface area=pxh+2xb
p=perimeter of base
h=height
b=area of base
Perimeter of base=5+5+2+2=14
h=3
area of base=5x2=10
Surface area=14x3+2x10
surface area=42+20
surface area=62
(x+40):12=88-78
(x+40):12=10
x+40=10*12
x+40=120
x=120-40
x=80
The slope-intercept form:
m - slope (a rate of change)
b - y-intercept
We have the slope
and point (3, -5). Substitute:
<em>add 9 to both sides</em>
Answer:
Quadratic formula = (-b +- sqrt(b^2 - (4ac))) / 2a
and
then simplify and solve