Step-by-step explanation:
tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)
= (sin2B + cos2B)/[(cosB)(sinB)]
= 1/[(cosB)(sinB)]
= (1/cosB)(1/sinB)
= (secB)(cscB)
Answer:
perpendicular
Step-by-step explanation:
To determine if AB and CD are parallel, perpendicular, or neither, we need to get the slope of AB and CD first
Given A (−1, 3), B (0, 5),
Slope Mab = 5-3/0-(-1)
Mab = 2/1
Mab = 2
Slope of AB is 2
Given C (2, 1), D (6, −1)
Slope Mcd = -1-1/6-2
Mcd = -2/4
Mcd = -1/2
Slope of CD is -1/2
Take their product
Mab * Mcd = 2 * -1/2
Mab * Mcd = -1
Since the product of their slope is -1, hence AB and CD are perpendicular
Answer:
x^-5 = x to the power of negative 5
Step-by-step explanation:
Which of these is equivalent to 1 over x to the power of 5 ?
Mathematically this is expressed as
(1/x)⁵
We have a rule when it comes to expressing power
(1/a)^b = a^-b
Hence, applying this rule to our question
(1/x)⁵ = (1/x)^5
= x^-5
This is written in words as:
x to the power of negative 5
