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pav-90 [236]
3 years ago
5

Mike is catering a party. He plans on having 4 trays of 5 appetizers each on the buffet at the beginning of the party and will r

otate in new trays as those become empty. To ensure that he does not run out of appetizers during the party, he is going to make 2 appetizers per person in addition to the initial number put out on the buffet. Which of the following represents A, the amount of appetizers Mike needs to make, in terms of p, the amount of people attending the party?
Mathematics
2 answers:
ASHA 777 [7]3 years ago
5 0

Answer:

A = 20 + 2p

Step-by-step explanation:

Eddi Din [679]3 years ago
5 0
I can’t see tour answer choices, but I’ll give an equation that will hopefully match one. Feel free to add in the comments what the answer choices are, and I will follow up.

A = 4(5) + 2p
A = 20 + 2p
A = 2p + 20
A = 2(p + 10)

I’m getting the 20 from the 4 trays of 5 appetizers on the buffet. I’m getting the 2p from the “two appetizers per person”
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Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all
DanielleElmas [232]

find y=mx+b for line parallel to AB.

The line that is parallel will have the same slope as line AB:

the slope of line AB is

m=(8-3)/(-10-2)

=5/-12

=-5/12

Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).

at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.

To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so

4+4=8

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%
Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

The domain refers to all values of x for which the function is defined.

The function is defined for

x^4+x^3-4x^2-4\ne0

This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0
3 years ago
Solve for x<br> Urgent need help
fiasKO [112]
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2

x = -8, 3/2</span>
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4 years ago
Which expression is equivalent to the expression below?
yaroslaw [1]

Answer:

6g

Step-by-step explanation:

I think it is this answer

5 0
3 years ago
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Find two positive numbers satisfying the given requirements.
Umnica [9.8K]

Answer:

8 and 19

Step-by-step explanation:

To some this, let's first list all the factors of 152. They are;

1, 2, 4, 8, 19, 38, 76, 152.

Now, let's arrange them to reflect being multiplied to get 152.

Thus;

1 × 152 = 152

2 × 76 = 152

4 × 38 = 152

8 × 19 = 152

Also, let's do the same for their sum;

1 + 152 = 153

2 + 76 = 78

4 + 38 = 42

8 + 19 = 27

Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19

8 0
3 years ago
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