Yes, in a function you cannot have two different images for the same x.
Because if an x has more than one image, you couldn't tell what is the value of the image given that x.
Answer:

Step-by-step explanation:
We can use the Law of Sines to find segment AD, which happens to be a leg of
and the hypotenuse of
.
The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is
. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

Now use this value in the Law of Sines to find AD:

Recall that
and
:

Now that we have the length of AD, we can find the length of AB. The right triangle
is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio
, where
is the side opposite to the 30 degree angle and
is the length of the hypotenuse.
Since AD is the hypotenuse, it must represent
in this ratio and since AB is the side opposite to the 30 degree angle, it must represent
in this ratio (Derive from basic trig for a right triangle and
).
Therefore, AB must be exactly half of AD:

Answer:
Answer:18+4.5
Step-by-step explanation:
This shape is a triangle with a semicircle connected to it
and this triangle is a right triangle so side A=B
that means the other leg is 6.Knowing that we can solve
The formula for the area of a triangle is (base×height)÷2
so that means 6×6 equals 36 and if you divide that by 2 you get the 18.
Now we will deal with the semicircle. We know that both of the legs are 6 so that means the diameter is 6 and now we solve 6 divided by 2 equals 3 and we will have to square that and we will 9 and since it is a semicircle we have to divide it by 2 and that will give us 4.5 and since we have to express it in terms of pi it will be 4.5(pi) and then we add both of the areas
giving us 18+4.5(pi)
and do you go to RSM
The digit 7 is in the tens place so 74 will become either 70 or 80 after rounding off to the nearest ten. Draw a number line with 3 numbers on it: 70, 75 and 80. (Both possible rounded off numbers and the number in the middle.