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Digiron [165]
3 years ago
5

Como leer el decimal 0.000000215

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

cero con doscientas quince mil millonésimas

Step-by-step explanation:

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Assume a bank loan requires an interest payment of $85 per year and a principal payment of $1,000 at the end of the loan's eight
Alex

Answer:

$919.98

Step-by-step explanation:

To solve using a financial calculator do

N=8

I/Y=10

PMT=85

FV=1000

CMPT PV get 919.98

To do by hand find the present value of the interst payments

85*(1-(1/1.1)^8)

which is 453.4687

Find the present value of the final ballon payment

1000*(1/1.1)^8

which is 466.507

take the sum

466.507+453.4678= 919.98

3 0
3 years ago
A 4-person relay team ran a race in 48 seconds. What was the<br> average time for each person?
lakkis [162]

Answer:12 secondes

Step-by-step explanation:48 seconds/ 4 people= 12 second

4 0
3 years ago
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Help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
yaroslaw [1]

Answer:

The answer is 4z^2 + 7z

Step-by-step explanation:

7z + 4z^2 +6 - 6

So, just combine like term which is 6 - 6 = 0

So, the remaining is 4z^2 + 7z that cannot be simplified anymore

7 0
2 years ago
Factor the expression using the GCF.
ss7ja [257]

Answer:

= 3 (3x + 5y)

Step-by-step explanation:

First find the GCF of 9 and 15 which would be 3. Then the GCF which is 3 is placed on the left of the parentheses. then you plug in the numbers. So 9x divided by 3 is 3x, and 15y divided by 3 is 5y.

7 0
2 years ago
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
2 years ago
Read 2 more answers
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