Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
The formula is to calculate the total admission fees collected is = F5*B14
1. Click on cell I5
2. Type equal sign =
3. Type F5 or click on F5 cell
3. Type multiplication sign *
4. Type B14 or click on B14 cell
Answer:
The answer is "False"
Explanation:
It is put to use Six Sigma had 3.4 defects per million opportunities (DPMO) from the start, allowing for a 1.5-sigma process shift. However, the definition of zero faults is a little hazy. Perhaps the area beyond 3.4 DPMO is referred to by the term "zero faults.", that's why Before being released, large computer programs, such as operating systems, must have no faults the wrong choice.