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coldgirl [10]
3 years ago
9

A normal body temperature for a human is approximately 98° Fahrenheit. What is this temperature in degrees Celsius? Round your a

nswer to the nearest tenth.
Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

37°C

Step-by-step explanation:

The normal body temperature of a human is 98°F. To convert it into Celsius we know the realtion between Celsius and Farenheight as ,

➳ C/5 = F -32/9

➳ C/5 = 98 - 32/9

➳ C/5 = 66/9

➳ C = 66/9 × 5

➳ C = 36.66 °C ≈ 37°C

<h3><u>Hence the body temperature in Celsius measure is 37°C .</u></h3>
Alinara [238K]3 years ago
3 0

Answer:

36.7

Step-by-step explanation:

its right :)

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Which of the following is an arithmetic sequence?
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0,2,4,6

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This sequence is arithmetic because the same number is being added each time: 2. With the others, the number being added changes every time.

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3 years ago
May someone help me with this problem?
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Answer:

a. \:  \:  \frac{ {4x}^{6} }{ {y}^{3} }  \\

b. \:  \:  \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } }  \\

Step-by-step explanation:

<h3>a. </h3>

{( {4x}^{ - 2} y)}^{ - 3}  \\  {4x}^{ - 2 \times  - 3}  \:  \: {y}^{1 \times  - 3}  \\  {4x}^{6}  {y}^{ - 3}  \\  \frac{ {4x}^{6} }{ {y}^{3} }  \\

<h3>b.</h3>

{( {8x}^{6} {y}^{ - 3})  }^{ \frac{1}{2} }  \\  {8x}^{6 \times  \frac{1}{2} } \:  \:  {y}^{ - 3 \times  \frac{1}{2} }   \\  {8x}^{3}  {y}^{  - \frac {3}{2} }  \\  \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\

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2 years ago
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J:V = 3:2

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Answer: Idek if that's a question

Step-by-step explanation:

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