Hello : here is a solution
Answer:
B
Step-by-step explanation:
Answer:
Infinite solutions
Step-by-step explanation:
1) First, you can solve this easily by elimination. Multiply the first equation by -2 in order to cancel out terms when adding to the second equation.
2) Then, add the new set of equations together. However, everything cancels out, bringing us to 0 = 0. This means that the lines the equations make must be the same. Thus, all real numbers must make this equation true, meaning that there are infinite solutions.
Answer:
Yes, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.
Step-by-step explanation:
Bilinear Transform:
In digital signal processing, the bilinear transform is used to convert continuous time system into discrete time system representation.
Minimum-Phase:
We know that a system is considered to be minimum phase if the zeros are situated in the left half of the s-plane in continuous time system. In the same way, a system is minimum phase when its zeros are inside the unit circle of z-plane in discrete time system.
The bilinear transform is used to map the left half of the s-plane to the interior of the unit circle in the z-plane preserving the stability and minimum phase property of the system. Therefore, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.
Answer:
x = all real numbers.
Step-by-step explanation:
3 x minus 8 = negative x + 4 (x minus 2)
3x - 8 = -x + 4(x - 2)
3x - 8 = -x + 4x - 8
3x - 8 = 3x - 8
3x - 3x = -8 + 8
0 = 0
Since the result is a true statement, but 0 = 0, x is equivalent to all real numbers.
Hope this helps!