This is not an equation and thus cannot be solved for x. Ensure that you have copied down the original problem exactly.
If, on the other hand, you meant x + 2x - 3 + x = - 4, you do have an equation and can solve for x as follows:
4x - 3 = -4 => 4x = -1 => x = -1/4
You can change it to Slope-Intercept form. That’s what I do as it’s easier to tell what is the slope and the y-intercept.
y=mx+b
2x + 3y = 6
3y = -2x + 6
y = -2/3x + 2
Steps:
Isolate y (move 2x to the other side) and change the sign of 2x (positive to negative). Divide everything in the equation by 3 in order to get y by itself.
Now that you have the equation, the slope is -2/3 and the y-intercept is 2. What I would do it start at 2 on the y axis and go down 2 units and to the right 3 units. The other way would be start at 2 on the y axis and go up 2 units on the y axis and then to the left 3 units. Your line should be a straight, diagonal line going down (in \ <— direction).
Hope this helped!! Tried to be as informative as possible.
Answer: z=67-at
————
a-45
Give the above guy brainliest
I'm assuming you are finding the equation of the line of Line J
Slope-intercept form: y = mx + b
[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]
For lines to be perpendicular, the slopes have to be negative reciprocals of each other. (basically changing the sign (+/-) and flipping the fraction/switching the numerator and the denominator)
For example:
slope = 2 or 
Perpendicular line's slope = 
[changed sign from + to -, and flipped the fraction]
slope = 
Perpendicular line's slope = 
[changed sign from - to +, and flipped the fraction]
Since you know the slope is 3, the perpendicular line's slope is 
. Plug this into the equation
y = mx + b
To find b, plug in the point (3, 8)
8 = -1 + b Add 1 on both sides to get "b" by itself
8 + 1 = -1 + 1 + b
9 = b
