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Lisa [10]
3 years ago
9

Does Howard University superscore ACT scores???

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
Do you mean Harvard? Because if so, yes I believe
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CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION?
Dimas [21]

Answer:

  B.  More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.

The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.

4 0
3 years ago
The Difference BETWEEN the CI and SI on a Certain sum of money for 2 years at 15% per annum is RS.180.Find the sum
klio [65]

Step-by-step explanation:

when the difference between CI and SI given then the sum =

difference (100/r)^2

given difference is Rs . 180

Rate of interest is 15%

sum = 180× (100/15)^2

180×10000/225

= 8000

8 0
3 years ago
Why would a bank want to loan someone money?
AVprozaik [17]

Answer: So they can help someone with good credit score

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is 1.08 to the power of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="
OlgaM077 [116]

Answer:

about \: 1.01551

Step-by-step explanation:

No it isn't, because:

{1.08}^{ \frac{1}{5} }  =  { \frac{108}{100} }^{ \frac{1}{5} }  =  { \frac{27}{25} }^{ \frac{1}{5} }  =  \sqrt[5]{ \frac{27}{25} }  = 1.01551

6 0
3 years ago
Find the approximate solution(s) to each of the following equations graphically. Use technology to support your
ser-zykov [4K]

Answer: x" = 5.69

Step-by-step explanation:

The graphic solution is attached.

Verifying the solution:

Existence condition: x > 0

2x - 4 = √x + 5

√x =2x - 4 - 5

√x =2x - 9 (²)

x = (2x - 9)²

x = 4x² - 36x + 81

4x² - 36x - x + 81 = 0

4x² - 37x + 81 = 0

Δ = -37² - 4.4.81 = 1369 - 1296 = 73

x = 37 ±√73/8                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          

x' = 3.55

x" = 5.69

checking:

2*3.55 - 4 = 3.1

√3.55 + 5 = 6.88 Its not the same ∴ 3.55 is not a solution

2*5.69 - 4 = 7.39

√5.69 + 5 = 7.39 ∴ it's the only solution

4 0
3 years ago
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