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Lisa [10]
3 years ago
9

Does Howard University superscore ACT scores???

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
Do you mean Harvard? Because if so, yes I believe
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I need help with this question ASAP!!!!!!!!!!!!
TiliK225 [7]
It 90 degrees because even though the side lengths change the angle measure doesn’t
5 0
3 years ago
Read 2 more answers
Find the value of x.<br>x 13 39​
Alex

Answer:

13x-39=39

13x=78

 the answer is x=6

6 0
3 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
BRAINLIEST MATH okurttttt
Zepler [3.9K]

In the given question, \sqrt{x-1}is shifted one unit to the right of \sqrt{x}

So, Option C is correct.

Step-by-step explanation:

The parent function is \sqrt{x} and transformed function is \sqrt{x-1}

So, Parent Function: \sqrt{x}

Transformed Function: \sqrt{x-1}

  • If transformed function is of type: g(x) = f(x-h), then the graph is shifted to right h units.

So, In the given question, \sqrt{x-1}is shifted one unit to the right of \sqrt{x}

So, Option C is correct.

Keywords: Transformations

Learn more about Transformations at:

  • brainly.com/question/2415963
  • brainly.com/question/3779181
  • brainly.com/question/5563823

#learnwithBrainly

4 0
3 years ago
What are the positive and negative square roots of 1,6007
Dmitry [639]

Answer: 126.52

Step-by-step explanation:

The square root of 16,007 is approximately 126.52

There are no negative square roots

4 0
3 years ago
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