Answer:B & E
Step-by-step explanation:
We can first rearrange the function to isolate y. Then, we can find the slope as the function is in the form y=mx+b.

Since parallel lines have the same slope, we can put the slope of 3/4 into the point slope form to get the answer.
<em>For reference, the point-slope form is </em>

The first line is found in option E, so option E is one of the correct options.
We can also move the x to the other side, as two of the 5 options have both variables on the left (B and C).

If we multiply the whole equation by -4, we can get rid of the fraction.

Hence, option B is also correct.
Answer:
The answer is below
Step-by-step explanation:
A student on the cross- county team runs 30 minutes a day as a part of her training. Write an equation to describe the relationship between the distance she runs in miles, D, and her running speed, in miles per hour, when she runs at a constant speed of 5.4miles per hour for m minutes, and then at b miles per hour for n minutes
Solution:
Given that the student runs for a total of 30 minutes per day. He runs at 5.4 miles per hour for m minutes, and then at b miles per hour for n minutes.
Hence:
m + n = 30
60 minute = 1 hour. Therefore, m minute = m/60 hour, n minute = n/60 hour.
The distance traveled is the product the speed in miles per hour and the time taken to cover the distance. Distance = speed * time
The total distance ran (D) is:
D = 5.4(m/60) + b(n/60)
Answer:
The answer is below
Step-by-step explanation:
Given that:
The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

a) For x < 2:

From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%
b) For x = 2:

For x = 11:

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337
c) For x = 11:

From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525
d) For x = 2:

For x = 5:

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845
e) For x = 5:

From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033