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Nataly_w [17]
2 years ago
15

A dance school has 54 students who learn salsa, and 23 of those students also learn ballet. There are 15 students who do not lea

rn salsa but learn ballet, and 10 students do not learn either salsa or ballet. Which table best shows the conditional relative frequency of rows for the data? Learn salsa Do not learn salsa Total Learn ballet 0.29 0.19 1 Do not learn ballet 0.39 0.13 1 Total 0.68 0.32 1 Learn salsa Do not learn salsa Total Learn ballet 0.61 0.39 1 Do not learn ballet 0.76 0.24 1 Total 0.68 0.32 1 Learn salsa Do not learn salsa Total Learn ballet 0.43 0.60 1 Do not learn ballet 0.57 0.4 1 Total 0.68 0.32 1 Learn salsa Do not learn salsa Total Learn ballet 0.23 0.15 1 Do not learn ballet 0.31 0.10 1 Total 0.54 0.25 1
Mathematics
2 answers:
blagie [28]2 years ago
7 0

Answer:

Learn ballet 0.23 0.15 1

Do not learn ballet 0.31 0.10 1

Total 0.54 0.25 1

klasskru [66]2 years ago
6 0

Answer:

This is because 23 students learn salsa and ballet. The second cell of the first row, Not Salsa and Ballet, will have 15. This is because 15 students do not learn salsa but learn ballet.

Step-by-step explanation:

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Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

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New receipts = 21, 145 and 11

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Answer:

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Step-by-step explanation:

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Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
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Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

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\sigma^2 =32.4

Solving (c): The standard deviation

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\sigma = \sqrt {\sigma^2 }

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0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store
g100num [7]

This question is incomplete, the complete question is;

The Millennium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20.00 plus 6.00% TAX. The cannon emits protons at a speed of 0.741 c with respect to the ship.

What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction?  0.911 ANS .

What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction?

(Use positive sign for the forward direction, and negative for the backward direction.)

Answer:

A)

the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

B)

the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Step-by-step explanation:

Given that;

speed of ship u = 0.525C

speed of proton emission v = 0.741C

Now When Cannon is shot in Forward Direction

Relativistic speed S is Calculated as;

S = (u+v) / ((1 + (uv))/c²)

we substitute (0.525 + 0.741 )C / ((1 + (0.525 × 0.741) C)/c²)

the C² cancel each other

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S = 1.266 / 1.389925

S = 0.9108 ≈ 0.911c

Therefore the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction is 0.911c

When Cannon is shot in Backward  Direction

Relativistic speed S is Calculated as;

S = ( u – v ) / ( 1 – uv / c ²)

S =  (0.525 - 0.741) C / ((1 - (0.525 × 0.741) C)/c²)

the C² cancel each other

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S = -0.3535c

The negative sign indicates that the proton is moving in the opposite direction of the ship. (backward)

Therefore the velocity of the protons in the resting frame when the cannon is shot in the backward direction -0.3535c.

7 0
2 years ago
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