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Deffense [45]
3 years ago
5

On december 1, jonas jewelry wholesale center started with an inventory of 1,000 watches. shipments of 168, 231, and 411 were se

nt out on january 3, february 8, and march 7, respectively. receipts of 21, 145, and 11 were received on january 8, february 22, and march 18. find the number of watches on hand as of march 18. 1,732 424 367 1,633
Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

1000-(168+231+411)\\\\=1000-810\\\\=190

New receipts = 21, 145 and 11

So, Number of watches on hand becomes :

190+(21+145+11)\\\\=367

Hence, Third option is correct.

You might be interested in
Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
3 years ago
Giving brainlyist to the person with the correct answer
KonstantinChe [14]

Answer:

10 x 20

Step-by-step explanation:

it's 10 on the side of the shaded area, and 20 on the opposing side, so in this case, it must be 10 x 20 = 200.

hope it helps

8 0
2 years ago
Read 2 more answers
If x=3+root8 and y =3- root 8 find 1/x^2+1/y^2
KonstantinChe [14]

Answer:

34

Step-by-step explanation:

x=3+√8

y =3-√8

now,

1/x^2+1/y^2

=1/(3+√8)² + 1/(3-√8)²

= [(3-√8)²+(3+√8)²] / (3+√8)²(3-√8)²            [L.C.M  = (3+√8)²(3-√8)² ]

=[(3-√8+3+√8)²-2(3-√8)(3+√8) ] / [(3+√8)(3-√8)]²  

=[6²-2.(3²-√8² )] / (3²-√8²)²                 [ a²+ b²=(a+b)²-2ab]

=[36-2(9-8) ]/ (9-8)²

=[36-2.1] / 1²

=34

3 0
3 years ago
Please help with this one
anyanavicka [17]

Ok this inequality tells you the number of devices you can have before the new plan costs more than the old plan. The new plan expression is $4.50x + $94m =  y ( total cost). The old plan is $175m = y (total cost). You can see m (number of months) in both equations, you don't need it this time since we're going to to compare both to one month. Since they're both equal to y you can make them equal to each other. $4.50x + $94 = $175. Now you want to figure when the new plan is less than the old plan you switch the equal sign for a less than sign. $4.50x + $94 < $175; this will help you find the inequality you want. From there just use algebraic steps to find that x has to less than 18 or

x < 18.

3 0
3 years ago
3x+8y=15 , 2x−8y=10
faltersainse [42]
I think is should be (5,0)
3 0
3 years ago
Read 2 more answers
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