No two <em>intergers</em> can solve this problem. If you're not in Algebra II yet, the answer is probably "none."
Just look at the factor pairs of 25:
1 × 25
-1 × 25
5 × 5
-5 × -5
Clearly none of those can add up to 6.
If you want the more complex answer, I'll show you how here. If you don't understand why it doesn't work, that's okay. I just want you to see that there's not an actual answer to the problem.
a+b = 6
a = 6-b
ab = 25
(6-b)b = 25
6b -b² = 25
-b² + 6b = 25
b² -6b = -25
Factor by splitting the middle.
Half of -6 is -3, (-3)² = 9. Add this to each side.
b² -6b + 9 = -16
Factor the perfect square trinomial.
(b-3)² = -16
Take the square root of each side.
b-3 = 4i
b = 3+4i
a+b = 6
a+3+4i = 6
a= 3-4i
<em>(The "i" stands for an imaginary number, specifically, the square root of -1.)</em>
42 - 2x is the answer because x is the variable standing in for the number that will be multiplied by 2 (2x means 2 times something) and decreased by just means minus. if you haven't gotten to doing 2x then do 42 - 2*x
To find the x value of the max of
f(x)=ax^2+bx+c
when a is negative (if a is positive, we find the minimum)
we do
-b/2a is the x value
to find the y value, we just sub that x value back into the function
so
R(x)=-0.2x^2+60x+0
-b/2a=-60/(2*0.2)=-60/-0.4=150
x value is 150
make 150 units
sub back to find revenue
R(150)=-0.2(150)^2+60(150)
R(150)=-0.2(22500)+9000
R(150)=-4500+9000
R(150)=4500
max revenue is achieved when 150 units are produced yeilding $4500 in revenue
Basically just what your answer means in terms of the situation for the 5th box, and then the 6th one you have to create a question that can be answered with the same solution as the original one
Answer:
62.3538290725
Step-by-step explanation:
Sorry That All I Could Get For You
