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3 years ago

Please help me !!!!!!

Mathematics

1 answer:

cestrela7 [59]3 years ago

4 0

Given:

The set of pair and graphs.

To find:

The domain and range.

Solution:

We know that,

Domain is the set of x-values or input values.

Range is the set of y-values or output values.

(a)

The given set of ordered pairs is

{(-3,3),(5,5),(-3,2),(5,3)}

Here, the x-coordinates are -3, 5, -3, 5.

A set contains distinct values.

Therefore, the domain is {-3,5}.

(b)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,1),(-1,0.5),(-1,3),(0,0),(0,2),(1,0.5),(1,3)(2,1)}

Here, the y-values are 1, 0.5, 3, 0, 2, 0.5, 3, 1.

Therefore, the range is {0, 0.5, 1, 2, 3}.

(c)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,3),(-1,3),(0,1),(2,4)}

Here, the x-values are -2, -1,0, 2.

Therefore, the domain is {-2,-1,0,2}.

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The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of

weqwewe [10]

Complete Question:

The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of D is five-halves the measure of Y. Find the measure of each angle of the deck.

Answer:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \angle R = 128.57 ^{\circ}$

Step-by-step explanation:

Given

Shape: Parallelogram DGRY

Dimension: $\angle D = \frac{5}{2}\angle Y$

Required

Find the measure of each angle

D and R are opposite sides & G and Y are also opposite sides.

So, we have:

$\angle D = \angle R = \frac{5}{2}\angle Y$

and

$\angle G = \angle Y$

The sum of angles is given as:

$\angle D + \angle G + \angle R + \angle Y=360^{\circ}$

Substitute values for $\angle D, \angle G \ \& \angle R$

$\frac{5}{2}\angle Y + \frac{5}{2}\angle Y + \angle Y + \angle Y = 360^{\circ}$

Take LCM

$\frac{5\angle Y + 5\angle Y + 2\angle Y+ 2\angle Y}{2}= 360^{\circ}$

$\frac{14\angle Y}{2}= 360^{\circ}$

Multiply both sides by $\frac{2}{14}$

$\frac{2}{14} * \frac{14\angle Y}{2}= 360^{\circ} * \frac{2}{14}$

$\angle Y= 360^{\circ} * \frac{2}{14}$

$\angle Y= \frac{ 360^{\circ} *2}{14}$

$\angle Y= \frac{720^{\circ}}{14}$

$\angle Y= 51.43 ^{\circ}$

So:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \frac{5}{2}\angle Y$

$\angle D = \frac{5}{2} * 51.43^{\circ}$

$\angle D = \frac{5* 51.43^{\circ}}{2}$

$\angle D = \frac{257.15^{\circ}}{2}$

$\angle D = 128.57 ^{\circ}$

Hence:

$\angle D = \angle R = 128.57 ^{\circ}$

8 0

2 years ago

4b - 5 + (-a-3) i = 7 * 8i

Rudik [331]

Answer:

Simplifying

4b + -5 + (-1a + -3) * i = 7 + -8i

Reorder the terms:

4b + -5 + (-3 + -1a) * i = 7 + -8i

Reorder the terms for easier multiplication:

4b + -5 + i(-3 + -1a) = 7 + -8i

4b + -5 + (-3 * i + -1a * i) = 7 + -8i

Reorder the terms:

4b + -5 + (-1ai + -3i) = 7 + -8i

Reorder the terms:

-5 + -1ai + 4b + -3i = 7 + -8i

Solving

-5 + -1ai + 4b + -3i = 7 + -8i

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + -1ai + 4b + 5 + -3i = 7 + 5 + -8i

Reorder the terms:

-5 + 5 + -1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: -5 + 5 = 0

0 + -1ai + 4b + -3i = 7 + 5 + -8i

-1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: 7 + 5 = 12

-1ai + 4b + -3i = 12 + -8i

Add '-4b' to each side of the equation.

-1ai + 4b + -4b + -3i = 12 + -4b + -8i

Combine like terms: 4b + -4b = 0

-1ai + 0 + -3i = 12 + -4b + -8i

-1ai + -3i = 12 + -4b + -8i

Add '3i' to each side of the equation.

-1ai + -3i + 3i = 12 + -4b + -8i + 3i

Combine like terms: -3i + 3i = 0

-1ai + 0 = 12 + -4b + -8i + 3i

-1ai = 12 + -4b + -8i + 3i

Combine like terms: -8i + 3i = -5i

-1ai = 12 + -4b + -5i

Divide each side by '-1i'.

a = -12i-1 + 4bi-1 + 5

Simplifying

a = -12i-1 + 4bi-1 + 5

Reorder the terms:

a = 5 + 4bi-1 + -12i-1

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2 years ago

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A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13 What is the: Total Surface Area of the Prism

sdas [7]

Given:

A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13.

To find:

The total surface area of the prism.

Solution:

We have,

Height of prism = 7½ = 7.5

Sides of triangular base are 5, 12, 13. These sides of Pythagorean triplets because

$5^2+12^2=13^2$

$25+144=169$

$169=169$

So, the base of the prism is a right triangle.

Area of a triangle is

$Area=\dfrac{1}{2}\times base \times height$

$A_1=\dfrac{1}{2}\times 5\times 12$

$A_1=30$

The area of the base is equal to the area of the top, i.e., $A_2=30$ sq units.

Perimeter of the base is

$P=5+12+13$

$P=30$

The curved surface area of the prism is

$CSA=\text{Perimeter of the base}\times \text{Height of the prism}$

$CSA=30\times 7.5$

$CSA=225$

Now, the total area of the prism is

$A=A_1+A_2+CSA$

$A=30+30+225$

$A=285$

Therefore, the total surface area of the triangular prism is 285 square units.

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2 years ago

How many square metre of carpeting are needed to cover a floor that measures 8m by 5m

grigory [225]

Answer:

40 meters squared

Step-by-step explanation:

8 * 5 = 40

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3 years ago

Campbell Middle school has 912 students.How many computers are in this schools computer lab?

Aleksandr [31]

You can't really determine the amount of computers from this question, they're obviously not going to have one computer for everyone so half third, or even a fourth of the school population

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3 years ago

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