All categories

3 years ago

Please help me !!!!!!

Mathematics

1 answer:

cestrela7 [59]3 years ago

4 0

Given:

The set of pair and graphs.

To find:

The domain and range.

Solution:

We know that,

Domain is the set of x-values or input values.

Range is the set of y-values or output values.

(a)

The given set of ordered pairs is

{(-3,3),(5,5),(-3,2),(5,3)}

Here, the x-coordinates are -3, 5, -3, 5.

A set contains distinct values.

Therefore, the domain is {-3,5}.

(b)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,1),(-1,0.5),(-1,3),(0,0),(0,2),(1,0.5),(1,3)(2,1)}

Here, the y-values are 1, 0.5, 3, 0, 2, 0.5, 3, 1.

Therefore, the range is {0, 0.5, 1, 2, 3}.

(c)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,3),(-1,3),(0,1),(2,4)}

Here, the x-values are -2, -1,0, 2.

Therefore, the domain is {-2,-1,0,2}.

You might be interested in

Ed deposited $6000 into a savings account 4 years ago. The simple interest rate is 3%. How much does Ed have in his account now?

Serga [27]

Answer:

$200,000

Step-by-step explanation:

6,000×100=600,000

600,000÷3=200,000

So $200,000

8 0

3 years ago

Read 2 more answers

Please Help im on a test.<br>

Luda [366]

Answer:

225 square centimeters

Step-by-step explanation:

6 0

3 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +

timama [110]

Looks like your function is

$f(x)=\dfrac x{6x^2+1}$

Rewrite it as

$f(x)=\dfrac x{1-(-6x^2)}$

Recall that for $|x|$ , we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

If we replace $x$ with $-6x^2$ , we get

$f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}$

By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2$

Solving for $x$ gives the interval of convergence,

$|x|^2$

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0

2 years ago

Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i

mash [69]

Complete Question

A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?

Answer:

The margin of error is $E = 0.7$

The sample mean is $\= x = 4.2$

Step-by-step explanation:

from the question we are told that

The upper limit is $k = 4.9$

The lower limit is $r = 3.5$

Generally the margin of error is mathematically represented as

$E = \frac{k - r}{ 2}$

$E = \frac{ 4.9 - 3.5 }{2}$

$E = 0.7$

Generally the sample mean is mathematically evaluated as

$\= x = k - E$

=> $\= x = 4.9 - 0.7$

=> $\= x = 4.2$

4 0

3 years ago

A quality-assurance inspector periodically exam-ines the output of a machine to determine whether it is properly adjusted. When

Stolb23 [73]

Answer:

Step-by-step explanation:

From the given information;

The null hypothesis & alternative hypothesis:

$\mathbf{H_o:\mu = 2} \\ \\ \mathbf{H_1 : \mu \ne 2}$

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$Z = \dfrac{2.025- 2}{\dfrac{0.07}{\sqrt{35}}}$

$Z = \dfrac{0.025}{\dfrac{0.07}{\sqrt{35}}}$

$Z =2.11$

The p-value = 2(Z > 2.11) since this is a two-tailed test

The p-value = 2( 1 - Z < 2.11)

The p-value = 2 (1 -0.9826)

The p-value = 2 (0.0174)

The p-value = 0.0348

Decision Rule: To reject the $\mathbf{H_o}$ if the p-value is less than $\mathbf{H_o}$

Conclusion: We fail to reject $\mathbf{H_o}$ and conclude that the population mean = 2, thus the machine is properly adjusted.

4 0

2 years ago