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harkovskaia [24]
3 years ago
6

The process of learning by making mistakes and by trial and error is called _____.

Computers and Technology
1 answer:
vodomira [7]3 years ago
6 0
I believe it’s problem solving.
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Description:
Nastasia [14]

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

<em>int convert(float miles) </em>

<em>{ </em>

<em>    return miles * 5280; </em>

<em>} </em>

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

<em>    while(response == 'y') </em>

<em>    { </em>

<em>    cout<<"How many miles did you walk?. "; </em>

<em>    cin>>miles; </em>

<em>    cout<<"You walked "<<convert(miles)<<" feet"<<endl; </em>

<em>    cout<<"Continue? (y/n): "; </em>

<em>    cin>>response; </em>

<em>    } </em>

   cout<<"Bye!";

8 0
3 years ago
What two actions does the RETI instruction perf orm? Why must these two actions be done in a single instruction, as opposed to a
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Answer:

In assembly language, two instructions control the use of the assembly language procedure.

  • CALL
  • RET

CALL pushed the control to the return address onto the stack and transferred the control.

RET instruction returns the address that placed on the stack by a call instruction.

Explanation:

Action RET instruction

  • The RET instruction pops the address and returns off the stack, which is pointed by the stack pointer.
  • The stack is LIFO in memory at a particular location, and the pointer points offset from the stack location.

RET instruction does its job by consulting the register and memory state at the point when it is executed.

In RET instruction, only register and memory state is executed. Call instruction must save that address that figure out in a register and memory location.

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You place a new disc in an optical drive, and then double-click the drive in the operating system's file browser interface. An e
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Answer:

Wait. Then you try it again

Explanation:

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