What is the answer only right answers<br>

A device that makes it possible for multiple customers to share one address is called a/n _____.

Debora [2.8K]

When you use the word "address", I assume you are referring to an external address, in which case the answer is NAT (network address translation). Essentially, network address translation converts LAN IP addresses (local IP addresses) to WAN IP addresses (external IP addresses). So for instance: everyone in my home accesses the internet under our network's external IP address. Inside our network, we have local IP addresses, which allow for packets to be routed to our individual machines wirelessly. So let's say my IP address on the LAN is 192.168.1.4, and I want to access brianly.com. My router performs NAT by converting my local IP to an external one which can be used for accessing the web. Then when data comes back to the network from brainly's server, my router once again performs NAT to convert between my external IP to my local IP, so that my router knows where the data needs to be routed to on the LAN.

6 0

3 years ago

Write smallest to largest: Byte, bit, MB, PB, GB, nibble

OlgaM077 [116]

Answer:

bit
nibble
byte
MB
GB
PB

Explanation:

this is it!!!

3 0

3 years ago

Read 2 more answers

C++

daser333 [38]

#include<iostream>

#include <fstream>

#include <vector>

#include <string>

#include "StatePair.h"

using namespace std;

int main() {

ifstream inFS;

int zip;

int population;

string abbrev;

string state;

unsigned int i;

vector<StatePair <int, string>> zipCodeState;

vector<StatePair<string, string>> abbrevState;

vector<StatePair<string, int>> statePopulation;

inFS.open("zip_code_state.txt");

if (!inFS.is_open()) {

cout << "Could not open file zip_code_state.txt." << endl;

return 1;

}

while (!inFS.eof()) {

StatePair <int, string> temp;

inFS >> zip;

if (!inFS.fail()) {

temp.SetKey(zip);

}

inFS >> abbrev;

if (!inFS.fail()) {

temp.SetValue(abbrev);

}

zipCodeState.push_back(temp);

}

inFS.close();

inFS.open("abbreviation_state.txt");

if (!inFS.is_open()) {

cout << "Could not open file abbreviation_state.txt." << endl;

return 1;

}

while (!inFS.eof()) {

StatePair <string, string> temp;

inFS >> abbrev;

if (!inFS.fail()) {

temp.SetKey(abbrev);

}

getline(inFS, state);

state = state.substr(0, state.size()-1);

if (!inFS.fail()) {

temp.SetValue(state);

}

abbrevState.push_back(temp);

}

inFS.close();

inFS.open("state_population.txt");

if (!inFS.is_open()) {

cout << "Could not open file state_population.txt." << endl;

return 1;

}

while (!inFS.eof()) {

StatePair <string, int> temp;

getline(inFS, state);

state = state.substr(0, state.size()-1);

if (!inFS.fail()) {

temp.SetKey(state);

}

inFS >> population;

if (!inFS.fail()) {

temp.SetValue(population);

}

getline(inFS, state);

statePopulation.push_back(temp);

}

inFS.close();

cin >> zip;

for (i = 0; i < zipCodeState.size(); ++i) {

}

for (i = 0; i < abbrevState.size(); ++i) {

}

for (i = 0; i < statePopulation.size(); ++i) {

}

Statepair.h

#ifndef STATEPAIR

#define STATEPAIR

#include <iostream>

using namespace std;

template<typename T1, typename T2>

class StatePair {

private:

T1 key;

T2 value;

public:

StatePair()

{}

void SetKey(T1 key)

{

this->key = key;

}

void SetValue(T2 value)

{

this->value = value;

}

T1 GetKey() { return key;}

T2 GetValue() { return value;}

void PrintInfo()

{

cout<<key<<" : "<<value<<endl;

}

};

3 0

2 years ago

Consider the following code: public static void mystery(int a) { System.out.println("A"); } public static void mystery(double a)

Feliz [49]

Answer:

The output is "A"

Explanation:

public class Solution {

public static void main(String args[]) {

mystery(7);

}

public static void mystery(int a) { System.out.println("A"); }

public static void mystery(double a) { System.out.println("B"); }

public static void mystery(int a, double b) { System.out.println("C"); }

public static void mystery(double a, int b) { System.out.println("D"); }

}

In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.

In the first case; mystery will be called if the argument is int.

In the second case; mystery will be called if the argument is double.

In the third case; mystery will be called if the arguments are int and double.

In the fourth case; mystery will be called if the arguments are double and int.

When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".

3 0

3 years ago

A department manager would like to choose an access control model in which the owner of a resource decides who may modify permis

Hoochie [10]

Answer: Discretionary access control (DAC)

Explanation: Discretionary access control is the control system that is imposed over the information system. The information systems contains different objects and subjects that gets the permission to do the operations.

The operation which the components can do are sharing the data to other object or subjects, privilege providence, change in the rules for the access, security entities getting changed etc.

4 0

3 years ago

What is the answer only right answers​

What is the answer only right answers