Assume a 8x1 multiplexer’s data inputs have the following present values: i0=0, i1=0, i2=0, i3=0, i4=0, i5=1, i6=0, i7=0. What s
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Answer:
Here is the C++ program:
#include<iostream> //to use input output functions
#include <algorithm> //to use tolower() function
using namespace std; //to identify objects like cin cout
int main() { //start of main function
string text; // to hold text input
cout<<"Enter a line of text: "; // prompts user to enter a string
getline(cin,text); // reads the input string (text) from user
transform(text.begin(), text.end(), text.begin(), ::tolower); //converts the text into lower case
int letter[26] = {0}; //to hold the letters
int i; // used as a loop variable
int words=0; // to hold the count of words
for(i = 0; i< text.size();i++){ // iterates through the text
if(isalpha(text[i])&&(text[i+1]=='.'||text[i+1]==','||text[i+1]==' ')) //checks if the character at i-th index of text is a letter, and checks if i+1 index position of text is a period, comma or a space
words++; // adds 1 to the count of words
if(isalpha(text[i])) // if the character at the i-th index of text is a letter
letter[text[i]-'a']++; } // counts the occurrences of each letter
char j = text[text.size()-1]; // sets j to the last character of text
if(j != '.' && j!= ' '&& j!=',' &&j!= '\0') //if the last character is not a period or empty space or comma or end of lone
words++; //add 1 to the count of words
cout<<"Number of words: "<<words<<endl; //display the number of words in the text
for(i=0; i<26; i++) { //iterates 25 times
if(letter[i]>0) //if letter at index i is greater than 0
cout<<(char)('a'+i)<<" : "<<letter[i]<<endl; }} //displays each letters and its number of occurrences in the text
Explanation:
The program is explained in the attached document with an example.
