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3 years ago

13

There are 10 pieces of candy in a bowl and 2 of them are chocolate. What percentage of the pieces of candy in the bowl are choco

late?

1 answer:

zhenek [66]3 years ago

6 0

Answer:

20%

Explanation:

2 out of 10 is the same as 20 out of 100. So 2/10 = 2/100 or 20%

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Oh, no... you dropped your study flashcards, and now they're out of order! Put them back into the correct order for a eukaryotic

Vladimir79 [104]

The given question is incomplete, the complete question is:

Oh, no... you dropped your study flashcards, and now they're out of order! Put them back into the correct order for a eukaryotic cell.

a. "Combine the mRNA strand with a ribosome and a tRNA carrying a methionine."

b. "Unwind the DNA molecule near the promoter."

c. "Exit the nucleus to the cytoplasm."

d. "Transcribe the complementary RNA strand."

[Tip: you might want to work out the correct order on a piece of scratch paper before selecting from the options below.]

c - d - b - a

b - d - c - a

c - b - d - a

d - b - c - a

b - d - a - c

Answer:

The correct order would be b, d, c, a.

Explanation:

First unwinding of the molecule of DNA takes place close to the promoter. After that transcription of the complementary RNA strand takes place, then mRNA moves out of the nucleus into the cytoplasm. Ultimately, the combination of ribosome and tRNA carrying a methionine takes place with the mRNA.

The order is based upon the central dogma of the cell. Based on the central dogma concept, the transcription of the mRNA takes place in the first place, which then gets transported out of the nucleus into the cytoplasm in the eukaryotic cell. The unwinding of DNA takes place close to the sequence of the promoter for the process of transcription.

In the promoter region, various transcription factors are present and binding of RNA polymerase takes place with the template strand. The generated mRNA then get transported out of the nucleus into the cytoplasm. Post transcription, translation of mRNA takes place with the assistance of tRNA and ribosome. In the mRNA, the start codon generally codes for methionine because of which the tRNA that carries methionine identifies the start codon, and the process of translation gets initiated.

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During which process is mRNA converted into a sequence of amino acids for protein production?

slava [35]

Answer:

Translation

Explanation:

When assembled in the nucleus, mRNA peels off and moves to the cytoplasm. Here, it attaches to a ribosome. As the mRNA moves along the ribosome its information is translated into the appropriate amino acids which are assembled into a polypeptide.

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What are the sugars the algae produce primarily used for?

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Answer: Algae use photosynthesis to convert CO2 and sunlight into sugars and then convert some of the sugars into oil, which can be harvested and converted to biodiesel. 4) 30x more oil per hectare than other plants used for biodiesel such as soybean, oil palms, and rapeseed.

Hope it helps :)

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3 years ago

Read 2 more answers

Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe

Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

$p+q=1\\(p+q)^{2} = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1$

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, $P(aa)=q^{2}=0.000588$ . And with that we can calculate the value of q,

$P(a)=q=\sqrt{0.000588}=0.024$

And since we know that p+q=1, we can find out the value of p.

$p+0.024=1\\1-0.024=p\\p=0.976$

Next, we find out the genotypic frequency of the genotype AA:

$P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95$

Now, we can find out the genotypic frequency of the genotype Aa:

$P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046$

Notice than:

$p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1$

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

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