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MariettaO [177]
3 years ago
8

Which of the following do you use to tell whether a relationship is proportional or not?

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

The correct option to tell whether a relationship is proportional or not is;

\dfrac{y}{x}

Step-by-step explanation:

A proportional relationship is a relationship between two variables, 'x', and 'y' such that they have equivalent ratio, such that all values of variable 'y' are given by the product of the values of the variable 'x' and a constant, 'k'

Therefore, y = k · x, from which we have;

\dfrac{y}{x} = k = Contant

Therefore we can use \dfrac{y}{x} to tell whether a relationship is proportional or not proportional.

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Please help! Will give brainliest to correct answer
saveliy_v [14]

Answer:

Correct option is (C).

Step-by-step explanation:

Because in figure,

°.°point B is fixed at plane.

.°.Center is B.

& °.° Image is enlargement.

.°. scale factor will be greater than 1

Now,

scale factor = A'B'/AB

= 24/6

= 3

So correct option is (C).

#$# HOPE YOU UNDERSTAND #$#

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5 0
3 years ago
What is the equation of the line shown in this graph? ​
san4es73 [151]

Answer:

y=-3

Step-by-step explanation:according to the graph, for all values of x, y is equal to -3, so this function is independent of the variable x, so the equation is y=-3 (constant for all values of the Real numbers)

4 0
3 years ago
In an ore, 9.8% of its total weight is metal. How many pounds of metal are in 1,950 lb of ore?
Fudgin [204]

Answer

Find out the  how many pounds of metal are in 1,950 lb of ore .

To proof

let us assume that the pounds of metal are in 1,950 lb of ore be x .

As given

In an ore, 9.8% of its total weight is metal.

ore weight = 1,950 lb

9.8% is written in the decimal form

= \frac{9.8}{100}

= 0.098

Than the equation becomes

x = 0.098 × 1950

x = 191.1 pounds

Therefore the 191.1 pounds of metal are in 1,950 lb of ore .

Hence proved



5 0
3 years ago
Which values are within the range of the piecewise-defined function? f(x) = StartLayout enlarged left-brace 1st Row 1st column 2
Otrada [13]

Answer:

the answer is below frum ed

Step-by-step explanation:

y= -6

Y= -4

Y= -3

Y= 0

8 0
2 years ago
Read 2 more answers
Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
Bingel [31]

Answer:

A)

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>B)</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em> Rejected H₀</em>

<em>There is a significant difference in drug resistance between the two states.</em>

C)

P - value = 0.0066

<em>P - value = 0.0066 < 0.02</em>

<em>D) </em>

<em>1) Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first sample size n₁ = 174</em>

Suppose that, of 174 cases tested in a certain state, 11 were found to be drug-resistant.

<em>First sample proportion </em>

                    p_{1} = \frac{x_{1} }{n_{1} } = \frac{11}{174} = 0.0632

<em>Given second sample size n₂ = 375</em>

Given data  Suppose also that, of 375 cases tested in another state, 7 were found to be drug-resistant

<em>Second sample proportion</em>

<em>                  </em>p_{2} = \frac{x_{2} }{n_{2} } = \frac{7}{375} = 0.0186<em></em>

<u><em>Step(ii):-</em></u>

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>        Where </em>

<em>         </em>P = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} +n_{2} }<em></em>

<em>        </em>P = \frac{174 (0.0632) + 375 (0.0186) }{174+375 } =  \frac{17.9718}{549} = 0.0327<em></em>

<em>       Q = 1 - P = 1 - 0.0327 = 0.9673</em>

<u><em>Step(iii):-</em></u>

<em></em>

<em>  Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>          </em>Z = \frac{0.0632-0.0186  }{\sqrt{0.0327 X 0.9673(\frac{1}{174 }+\frac{1}{375 } ) } }<em></em>

<em>       Z  =   2.7261</em>

<em>   </em>

<em>Level of significance = 0.02 or 0.98</em>

<em>The z-value = 2.054</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em>    Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

 <u><em>P- value </em></u>

<em>P( Z > 2.7261) = 1 - P( Z < 2.726)</em>

<em>                         = 1 - ( 0.5 + A (2.72))</em>

<em>                         = 0.5 - 0.4967</em>

<em>                          = 0.0033</em>

we will use two tailed test

<em>2 P( Z > 2.7261)  = 2 × 0.0033</em>

<em>                            = 0.0066</em>

<em>P - value = 0.0066 < 0.02</em>

<em>  Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

8 0
2 years ago
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