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3 years ago

Determine the domain and range of the given function. The domain is The range is

Mathematics

2 answers:

astra-53 [7]3 years ago

6 0

What is the function?

hoa [83]3 years ago

3 0

Domain: all values that go into a function
range: difference between the lowest and highest values

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If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

A town has a population of 15000 and grows at 4% every year. To the nearest year, how long will it be until the population will

3241004551 [841]

8197 years It’s exponential growth

7 0

2 years ago

Dimitri makes 6 bookcases in 8 days. What is his unit rate? I thought I had it, but I really didn't until I realized I was real

luda_lava [24]

He completes .75 of a bookcase per every day. That is, 3/4 or 75% of one bookcase per day.

7 0

3 years ago

What did the mathematician do to practice over winter break

lbvjy [14]

Answer:

I don't know what, I would like to know

8 0

3 years ago

PLEASE help i neeed help asap im willing to give u 100 or 40 points if u answer this correctly so please help answer them all

AURORKA [14]

Step-by-step explanation:

The hundredth place is the second number to the right of the decimal place (e.g., in ab.cd, where a, b, c, and d represent digits, the hundredth place is d).

When we round to the nearest hundredth, we remove all digits after the <em>thousandth</em> place. Then, if the thousandth place is 5 or greater, we remove it and add 0.01 (round up); if the thousandth place is 4 or lesser, we remove it (round down).

Thus:

50.30=50.30, as there is no thousandth place

50.20=50.20, same reasoning

56.90=56.90, same reasoning

49.50=49.50, same reasoning

51.10=51.10, same reasoning

30.00=30.00, same reasoning

5 0

2 years ago