An airplane is at an altitude of 1200 m, the angle of depression to a building at the airport on the ground measures 28∘. Find t
1 answer:
Answer:
The distance from the plane to the building is ___2553.2___meters.
Step-by-step explanation:
Given that An airplane is at an altitude of 1200 m.
The angle of depression to a building at the airport on the ground measures 28°.
We need to find the distance from the plane to the building.
Please check the attached diagram.
Let 'x' be the required distance in meters.
It forms a right-angled triangle as shown in the attached diagram.
The angle = Ф = 28°
The opposite to angle = 1200 meters
All we need to find the hypotenuse to determine the distance from the plane to the building.
Using the trigonometric ratio
sin θ = Perpendicular ÷ Hypotenuse
sin (28°) = 1200 ÷ x
x = 1200/sin (28°)
= 1200 / 0.47 ∵ sin (28°) = 0.47
= 2553.2 m
Thus, the distance from the plane to the building is ___2553.2___meters.
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Answer:
Step-by-step explanation:
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Given:
A train travels 288 km at a uniform speed.
If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
To find:
The initial speed of the train.
Solution:
Let x km/h be the initial speed on the train.
New speed of train = (x+4) km/h
We know that,
Time taken by the train initially to cover 288 km is hours.
New time taken by the train to cover 288 km is hours.
It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
Splitting the middle term, we get
We know that the speed cannot be negative. So, the only possible value of x is 32.
Therefore, the speed of the train is 32 km/h.