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Agata [3.3K]
3 years ago
13

Please find the missing side length?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

8

Step-by-step explanation:

43-35 i what you need to do so it is 8

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Literal Equations:<br> Solve for g. <br> m + n^2 = g5Q
Xelga [282]

I hope this helps you :)

8 0
3 years ago
Helpppppppppppppppppppp mathhhhhhhhh
sp2606 [1]
2) angle T Congruent to angle D; 3)angle s and angle u
7 0
3 years ago
Can anyone help please? Will give Brainly + 25 pts
Gennadij [26K]

Answer:

A. (f+g)(x) means add the two functions, f and g

  since f is 2x-2 and g is 6x, you'll just add them together

  (f+g)(x)=2x-2+6x = 8x+2

B. (f-g)(x) means subtract the two functions, f and g

  since f is 2x-2 and g is 6x, you'll just subtract

  (f-g)(x)=2x-2-6x = -4x+2

C. (g-f)(x) I think you're getting the hang of it!

 =6x-(2x-2)  just be sure to put the second function in parentheses because you're subtracting the whole thing

=6x-2x+2 = 4x+2

D. (g+f)(x) try this on your own and check here

6x+(2x-2) = 6x+2x-2 = 8x-2

Step-by-step explanation:

to add or subtract functions, don't let the function notation throw you off. Pretend each one is just a number and you just add or subtract the whole thing. You got it! Next they will give you something like find (f+g)(5). All that means is add the two functions like in part a, and then in the final answer, plug in 5 instead of x. For example (f+g)(5) = 8x+2 = 8(5) +2 = 42

:)

3 0
3 years ago
A train leaves Miami at 3:00 PM. A second train leaves the same city in the same direction at 8:00 PM. The second train travels
Anika [276]

Answer:

The first train travels at 58 mph and the second train travels at 203 mph.

Step-by-step explanation:

The first train left Miami at 3:00 PM.

The second train left Miami at 8:00 PM.

Let the speed of the first train be x.

The second train travels 145 mph faster than the first, that is 145 + x

The second train overtakes the first at 10:00 PM

This means that at 10:00 PM, they were both at the same location.

That is 7 hours after the first train left and 2 hours after the second train left.

Speed is given as:

s = d / t

where d = distance traveled and t = time taken

For the first train, after 7 hours traveling at speed x:

x = d / 7

=> d = 7x _______(1)

For the second train, after 2 hours, traveling at speed 145 + x:

145 + x= d / 2

=> d = 290 + 2x ____(2)

Equating (1) and (2):

7x = 290 + 2x

=> 7x - 2x = 290

5x = 290

=> x = 290/5 = 58 mph

Therefore, the first train travels at 58 mph and the second train travels at 203 mph (58 + 145)

4 0
3 years ago
The tangerine had 12 sections. I ate five sections. Dad ate 1/3. How much of the tangerine did we ate?
Kruka [31]
12-5=7 1/3 of 7=2.33333333

3 0
3 years ago
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