<span>Which of the following is the solution set of the equation
10(x^2+1/x^20)-63(x-1/x)=52=0
I think you type wrongly the equation:
It is : </span><span>10(x^2+1/x^2)-63(x-1/x)+52=0
We know: x</span>²+1/x²=(x-1/x)²+2, pose x-1/x=t and we have x²+1/x²=t²+2
So 10(t²+2)-63t+52=0
or 10t²-63t+72=0
we have t=(63+33):20= 24/5
and t=(63-33):20=3/2
+ If t=3/2 we have x-1/x=3/2 or 2x²-3x-2=0 and we have x=2, x=-1/2
+ Of t=24/5 we have x-1/x=24/5 or 5x²-24x-5=0 or x=5 and x=-1/5
And the answer: <span>c) (5,2,-1/5,-1/2)</span>
Answer:
Face
Step-by-step explanation:
Face is the correct answer.
CUBE is a three dimensional figure, so it's flat surface is called as FACE
1/5+1/5+1/5+1/5+1/5+1/5=6 divided
The answer is $13.96 because the markdown would’ve taken 5.99 off of the price
Answer: x = 2/3 and y = 2/3
Step-by-step explanation:
I've attached the solution.
From the solution, you get y = -5x + 4 and
y = x.
Now,
Put y = x in y = -5x + 4.
x = -5x + 4
6x = 4
x = 4/6
x = 2/3
So, y = 2/3 because y = x.
