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mars1129 [50]
3 years ago
11

Tthe rectangle below has an area of 12y^5 square meters and a width of 3y^3 meters

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

4y^2

Step-by-step explanation:

length \: of \: rectangle \\  =  \frac{area}{width}  \\ \\   =  \frac{12 {y}^{5} }{3 {y}^{3} }  \\  \\  = 4 {y}^{5-3}  \\  \\  \red{ \bold{ length \: of \: rectangle = 4 {y}^{2} }}

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What is the solution
antoniya [11.8K]

Answer:

3,2 or 1

Step-by-step explanation:

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3 years ago
Find the value of a and b<br><br> a^2 + b^2 = 400
Oliga [24]

Answer:

Step-by-step explanation:

a^2+b^2=400

a^2=400-b^2

a=sqrt(400-b^2) & -sqrt(400-b^2)

-----------------------------------------------

b^2=400-a^2

b=sqrt(400-a^2) & -sqrt(400-a^2)

7 0
3 years ago
Read 2 more answers
Gina measured the amount of water her friends drink each day in gallons. The line plot shows the measurements.
vova2212 [387]

Line plots are used to represent data using lines and dots

The difference between the greatest amount of water and the least is 1/2

From the line plot (see attachment), we have the following parameters:

Least = 8\frac 28

Greatest = 8\frac 68

<h3>Calculating the difference</h3>

The difference (d) is then calculated as:

d =Greatest -Least

So, we have:

d =8\frac 68 -8\frac 28

Subtract the common terms (8)

d =\frac 68 -\frac 28

Take LCM

d =\frac {6-2}8

d =\frac {4}8

Reduce the fraction

d =\frac {1}2

Hence, the difference between the greatest amount of water and the least is 1/2

Read more about line plots at:

brainly.com/question/3521995

7 0
2 years ago
River C is 400 miles longer than River D. If the sum of their lengths is 5,590 miles, what is the length of each river?​
pychu [463]

Answer:

River C is: 2,965 miles long.

River D is: 2,565 miles long.

Step-by-step explanation:

C=400+D\\C+D=5530

Have a great day! ^^

7 0
3 years ago
If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw
serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

\text{Depreciation rate}=\frac{15000+7000}{5}

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0
3 years ago
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